if -2 is a root of x^3-2x^2-3x+q, then q=?

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if -2 is a root of x^3-2x^2-3x+q, then q=?

Mathematics
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root(solution , zeros) is a point where line cross x-axis when y =0 so substitute y for 0 and x for -2 solve for q :)
?
what did you get ?

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im going to explain it to someone but idk how lol
im not sure how you did it
alright roots is a point where line intersect x-axis |dw:1440260821340:dw|
i think -10?
i replaced -2 with x and solved for q
i didn't get negative 10
q its not solution to this formal
q is constant not solution i know that but ti's not *negative 10
you can graph this equation x^3-2x^2-3x-10 graph it if graph of this equation intersect x-axis at -2 then it would be correct ....
u find q=10 right
i graphed both equations x^3-2x-3x+10 and -10
http://prntscr.com/87n277
\[\huge\rm (-2)^3-2(-2)^2-3(-2)+q=0\] solve for q
q=10
don't give ot direct answer it's against the coc .....
tnx no i need solution anyways
solve that equation for q what did you get ?
cause i need to explain it to someone
lol -8-8+6+q=0 , q-10=0 , q=10
i hope you can explain it now :=)

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