## anonymous one year ago if -2 is a root of x^3-2x^2-3x+q, then q=?

1. Nnesha

root(solution , zeros) is a point where line cross x-axis when y =0 so substitute y for 0 and x for -2 solve for q :)

2. anonymous

?

3. Nnesha

what did you get ?

4. anonymous

im going to explain it to someone but idk how lol

5. anonymous

im not sure how you did it

6. Nnesha

alright roots is a point where line intersect x-axis |dw:1440260821340:dw|

7. anonymous

i think -10?

8. anonymous

i replaced -2 with x and solved for q

9. Nnesha

i didn't get negative 10

10. dinamix

q its not solution to this formal

11. Nnesha

q is constant not solution i know that but ti's not *negative 10

12. Nnesha

you can graph this equation x^3-2x^2-3x-10 graph it if graph of this equation intersect x-axis at -2 then it would be correct ....

13. dinamix

u find q=10 right

14. Nnesha

i graphed both equations x^3-2x-3x+10 and -10

15. Nnesha
16. Nnesha

$\huge\rm (-2)^3-2(-2)^2-3(-2)+q=0$ solve for q

17. dinamix

q=10

18. Nnesha

don't give ot direct answer it's against the coc .....

19. anonymous

tnx no i need solution anyways

20. Nnesha

solve that equation for q what did you get ?

21. anonymous

cause i need to explain it to someone

22. dinamix

lol -8-8+6+q=0 , q-10=0 , q=10

23. Nnesha

i hope you can explain it now :=)