anonymous
  • anonymous
if -2 is a root of x^3-2x^2-3x+q, then q=?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Nnesha
  • Nnesha
root(solution , zeros) is a point where line cross x-axis when y =0 so substitute y for 0 and x for -2 solve for q :)
anonymous
  • anonymous
?
Nnesha
  • Nnesha
what did you get ?

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More answers

anonymous
  • anonymous
im going to explain it to someone but idk how lol
anonymous
  • anonymous
im not sure how you did it
Nnesha
  • Nnesha
alright roots is a point where line intersect x-axis |dw:1440260821340:dw|
anonymous
  • anonymous
i think -10?
anonymous
  • anonymous
i replaced -2 with x and solved for q
Nnesha
  • Nnesha
i didn't get negative 10
dinamix
  • dinamix
q its not solution to this formal
Nnesha
  • Nnesha
q is constant not solution i know that but ti's not *negative 10
Nnesha
  • Nnesha
you can graph this equation x^3-2x^2-3x-10 graph it if graph of this equation intersect x-axis at -2 then it would be correct ....
dinamix
  • dinamix
u find q=10 right
Nnesha
  • Nnesha
i graphed both equations x^3-2x-3x+10 and -10
Nnesha
  • Nnesha
http://prntscr.com/87n277
Nnesha
  • Nnesha
\[\huge\rm (-2)^3-2(-2)^2-3(-2)+q=0\] solve for q
dinamix
  • dinamix
q=10
Nnesha
  • Nnesha
don't give ot direct answer it's against the coc .....
anonymous
  • anonymous
tnx no i need solution anyways
Nnesha
  • Nnesha
solve that equation for q what did you get ?
anonymous
  • anonymous
cause i need to explain it to someone
dinamix
  • dinamix
lol -8-8+6+q=0 , q-10=0 , q=10
Nnesha
  • Nnesha
i hope you can explain it now :=)

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