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anonymous
 one year ago
A graph of 2 functions is shown below.
graph of function f of x equals negative 2 multiplied by x plus 3 and graph of function g of x equals x cubed plus 4 multiplied by x squared minus x minus 4
Which of the following is an approximate solution for f(x) = g(x)?
x = 1
x = −1
x = −4
x = 2
anonymous
 one year ago
A graph of 2 functions is shown below. graph of function f of x equals negative 2 multiplied by x plus 3 and graph of function g of x equals x cubed plus 4 multiplied by x squared minus x minus 4 Which of the following is an approximate solution for f(x) = g(x)? x = 1 x = −1 x = −4 x = 2

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Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Set the 2 equations to equal each other

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3the equations of your functions, are: \[\Large \begin{gathered} f\left( x \right) =  2x + 3 \hfill \\ g\left( x \right) = {x^3} + 4{x^2}  4 \hfill \\ \end{gathered} \] now, you have to establish, what vauel of x, among that you have listed above, is the one such that g(x)=f(x)

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0U get 2x+3=X powered 3+4x powered 2x4

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Simplify it so that 0 is on one side

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3for example, let's consider x=1, then we have: \[\Large \begin{gathered} f\left( {  1} \right) =  2 \cdot \left( {  1} \right) + 3 = 5 \hfill \\ g\left( {  1} \right) = {\left( {  1} \right)^3} + 4{\left( {  1} \right)^2}  4 =  1 + 4  4 =  1 \hfill \\ \end{gathered} \] so our value for x, can not be x=1

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Now u get X powered 3+4x powered 2+x7

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Which is all. Equal to 0

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Now, factor is to some thing like (x+a)(x+b)(x+c)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3plese, try with x=1, namely replace x with 1, into both functions f(x), and g(x), what do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[f(−4)=−2⋅(−4)+3=5g(−4)=(−4)^3+4(−4)^2−4=4+4−4=4?\]

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0I'll let u do it @Michele_Laino s way but with this, u get an approximation of 1

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3we have: \[\Large \begin{gathered} f\left( {  4} \right) =  2\left( {  4} \right) + 3 = 11 \hfill \\ g\left( {  4} \right) = {\left( {  4} \right)^3} + 4{\left( {  4} \right)^2}  4 =  64 + 64  4 =  4 \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3please compute these quantities: \[\Large \begin{gathered} f\left( 1 \right) = ... \hfill \\ g\left( 1 \right) = ... \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3we have: \[\Large \begin{gathered} f\left( 1 \right) =  2 \cdot 1 + 3 =  2 + 3 = 1 \hfill \\ g\left( 1 \right) = {1^3} + 4 \cdot {1^2}  4 = 1 + 4  4 = 1 \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you check one for me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait nvm! I got it !Thank you!
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