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anonymous

  • one year ago

please help me The graphs of f(x) and g(x) are shown below: graph of function f of x open upward and has its vertex at negative 7, 0. Graph of function g of x opens upward and has its vertex at negative 9, 0. If f(x) = (x + 7)2, which of the following is g(x) based on the translation?

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  1. anonymous
    • one year ago
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    http://broward.flvs.net/webdav/assessment_images/educator_algebraI_v20/segment2_graph33.gif

  2. Michele_Laino
    • one year ago
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    I'm sorry, I'm not able to see your graphs

  3. anonymous
    • one year ago
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    @Michele_Laino sorry i had an emergency hold on

  4. anonymous
    • one year ago
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    @Michele_Laino

  5. Michele_Laino
    • one year ago
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    hint: the graph of f(x), can be obtained from the graph of g(x), making a traslation by 2 units to right

  6. Michele_Laino
    • one year ago
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    or, vice versa, the graph of g(x), can be obtained from the graph of f(x), making a traslation by2 units to left

  7. Michele_Laino
    • one year ago
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    the last condition, can be expressed by this formula: \[\Large g\left( x \right) = f\left( {x + 2} \right)\]

  8. anonymous
    • one year ago
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    im still sort of confused

  9. anonymous
    • one year ago
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    If f(x) = (x + 7)2, which of the following is g(x) based on the translation? g(x) = (x + 9)2 g(x) = (x + 5)2 g(x) = (x − 9)2 g(x) = (x − 5)2 theres are the choice they gave me

  10. Michele_Laino
    • one year ago
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    in other words, you have to replace x, with x+2 into the expression of f(x), namely: \[\Large g\left( x \right) = f\left( {x + 2} \right) = {\left( {x + 2 + 7} \right)^2} = ...\]

  11. anonymous
    • one year ago
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    o ok it said +5 so i was totally confused

  12. anonymous
    • one year ago
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    ok so i understand it would be A then?

  13. Michele_Laino
    • one year ago
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    no, sorry I have made a typo

  14. anonymous
    • one year ago
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    so it isnt A?

  15. Michele_Laino
    • one year ago
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    yes! correct! it is option A

  16. anonymous
    • one year ago
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    ok thank you so much can you help with a few more?

  17. Michele_Laino
    • one year ago
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    ok!

  18. anonymous
    • one year ago
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    ok 1 sec please

  19. anonymous
    • one year ago
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    ok im ready Which graph shows the quadratic function y = 3x2 + 12x + 14?

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  20. anonymous
    • one year ago
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    @Michele_Laino

  21. Michele_Laino
    • one year ago
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    your function is a parabola, right?

  22. anonymous
    • one year ago
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    yes it is

  23. Michele_Laino
    • one year ago
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    the equation of the axis of your parabola, is: \[\Large x = - \frac{{12}}{{2 \cdot 3}} = ...\]

  24. Michele_Laino
    • one year ago
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    which is the x-coordinate of the vertex. please complete: \[\Large x = - \frac{{12}}{{2 \cdot 3}} = ...?\]

  25. anonymous
    • one year ago
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    -2?

  26. Michele_Laino
    • one year ago
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    correct! the equation of the axis of your parabola, is x=-2, furthermore, the x-coordinate of the vertex of your parabola, is also x=-2

  27. anonymous
    • one year ago
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    so the answer would be graph a because its the only one with negative 2 aas the x coordinate

  28. anonymous
    • one year ago
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    o nvm it could also be c

  29. anonymous
    • one year ago
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    but i think it is a

  30. Michele_Laino
    • one year ago
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    ok! we have to understand what is the right graph: A or C?

  31. anonymous
    • one year ago
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    i think a because its at -2,-2

  32. Michele_Laino
    • one year ago
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    the y-coordinate of your parabola is: \[\Large y = \frac{{4ac - {b^2}}}{{4a}}\] where a=3, b=12, and c=14

  33. Michele_Laino
    • one year ago
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    oops..it is the y-coordinate of the vertex of your parabola

  34. anonymous
    • one year ago
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    so it is not a?

  35. Michele_Laino
    • one year ago
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    so after a substitution, we get: \[\Large y = \frac{{4ac - {b^2}}}{{4a}} = \frac{{4 \cdot 3 \cdot 14 - {{12}^2}}}{{4 \cdot 3}} = ...?\] please complete

  36. anonymous
    • one year ago
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    1sec let me do it

  37. Michele_Laino
    • one year ago
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    ok!

  38. anonymous
    • one year ago
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    -2 again so it is a

  39. Michele_Laino
    • one year ago
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    are you sure? I got a different result

  40. Michele_Laino
    • one year ago
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    \[\large y = \frac{{4ac - {b^2}}}{{4a}} = \frac{{4 \cdot 3 \cdot 14 - {{12}^2}}}{{4 \cdot 3}} = \frac{{168 - 144}}{{12}} = ...?\]

  41. anonymous
    • one year ago
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    yes that what i got 168 - 144 i did it wrong its positive 2 but i used thos step

  42. anonymous
    • one year ago
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    so its c for some reason i added a negtive signat the end of the problem

  43. Michele_Laino
    • one year ago
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    correct! it is option C

  44. anonymous
    • one year ago
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    thank you so much

  45. Michele_Laino
    • one year ago
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    :)

  46. anonymous
    • one year ago
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    can u help with 1 more

  47. anonymous
    • one year ago
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    Which of the following represents the factored form of f(x) = x3 − 64x?

  48. anonymous
    • one year ago
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    @Michele_Laino

  49. Michele_Laino
    • one year ago
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    ok! I'm here

  50. anonymous
    • one year ago
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    k can you help me with this 1 Which of the following represents the factored form of f(x) = x3 − 64x?

  51. Michele_Laino
    • one year ago
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    yes!

  52. Michele_Laino
    • one year ago
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    first step: we can factor out x, so we can write this: \[\Large {x^3} - 64x = x\left( {{x^2} - 64} \right)\]

  53. Michele_Laino
    • one year ago
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    subsequently, we can use this algebraic identity: \[\Large {A^2} - {B^2} = \left( {A - B} \right)\left( {A + B} \right)\] where A=x, and B= 8

  54. anonymous
    • one year ago
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    we have to foil this right if so can you show me how i would set it up?

  55. Michele_Laino
    • one year ago
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    no, it is not necessary to apply the foil method, since we have to apply that standard identity

  56. Michele_Laino
    • one year ago
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    you should get this: \[\Large {x^2} - 64 = \left( {x - 8} \right)\left( {x + 8} \right)\]

  57. anonymous
    • one year ago
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    theses are the choices f(x) = x(x + 8)(x − 8) f(x) = (x − 8)(x + 8) f(x) = x(x − 8)2 f(x) = x(x2 − 8)

  58. Michele_Laino
    • one year ago
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    so, the complete factorization, is: \[\Large {x^3} - 64x = x\left( {{x^2} - 64} \right) = x\left( {x - 8} \right)\left( {x + 8} \right)\]

  59. anonymous
    • one year ago
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    o ok so i just needed to find wat squared equals 64 ok so its b

  60. Michele_Laino
    • one year ago
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    I think it is option A

  61. anonymous
    • one year ago
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    o ok you are right i see my error with the x variable

  62. anonymous
    • one year ago
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    ay thank you so much michele u were really helpfull :) lol and u have a sexy as name

  63. Michele_Laino
    • one year ago
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    thanks! :)

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