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coming.home

  • one year ago

I'm having some more trouble with this algebraic expression. a=2, b=3, and c=-6 12 - 2(a-b)^2 So when you substitute the variables for numbers you get: 12 - 2 (2-3) ^2. I'm a little stuck after there. Can anyone help me?

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  1. phi
    • one year ago
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    order of operations , do stuff in parens first what is 2-3 ?

  2. coming.home
    • one year ago
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    It would be -1.

  3. phi
    • one year ago
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    ok, now which operation do we do next ?

  4. coming.home
    • one year ago
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    Then you do exponents right? So the answer to that would be -1

  5. phi
    • one year ago
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    \[ 12 - 2 (2-3) ^2 \\ 12 - 2 (-1) ^2\] the exponent part is (-1)^2 which means -1*-1

  6. coming.home
    • one year ago
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    Ohhhh right. Okay so 1. The next step would be multiplication right? So that would be -2 * 1 which is... -2

  7. phi
    • one year ago
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    \[ 12 - 2 (2-3) ^2 \\ 12 - 2 (-1) ^2 \\ 12-2\cdot 1 \\ 12 -2 \]

  8. coming.home
    • one year ago
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    Awesome I got it right then! Thanks so much for your help,I understand now :) You were really helpful btw

  9. phi
    • one year ago
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    btw, we can treat 12 -2*1 as 12+ -2*1 which gives 12+ -2 = 10 or as 12 - 2*1 wich is 12 - 2 = 10 the first way we think of adding -2 then second way , we think of it as subtracting

  10. coming.home
    • one year ago
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    Oooooo thanks for the tip :)

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