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coming.home
 one year ago
I'm having some more trouble with this algebraic expression.
a=2, b=3, and c=6
12  2(ab)^2
So when you substitute the variables for numbers you get: 12  2 (23) ^2. I'm a little stuck after there. Can anyone help me?
coming.home
 one year ago
I'm having some more trouble with this algebraic expression. a=2, b=3, and c=6 12  2(ab)^2 So when you substitute the variables for numbers you get: 12  2 (23) ^2. I'm a little stuck after there. Can anyone help me?

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phi
 one year ago
Best ResponseYou've already chosen the best response.1order of operations , do stuff in parens first what is 23 ?

phi
 one year ago
Best ResponseYou've already chosen the best response.1ok, now which operation do we do next ?

coming.home
 one year ago
Best ResponseYou've already chosen the best response.1Then you do exponents right? So the answer to that would be 1

phi
 one year ago
Best ResponseYou've already chosen the best response.1\[ 12  2 (23) ^2 \\ 12  2 (1) ^2\] the exponent part is (1)^2 which means 1*1

coming.home
 one year ago
Best ResponseYou've already chosen the best response.1Ohhhh right. Okay so 1. The next step would be multiplication right? So that would be 2 * 1 which is... 2

phi
 one year ago
Best ResponseYou've already chosen the best response.1\[ 12  2 (23) ^2 \\ 12  2 (1) ^2 \\ 122\cdot 1 \\ 12 2 \]

coming.home
 one year ago
Best ResponseYou've already chosen the best response.1Awesome I got it right then! Thanks so much for your help,I understand now :) You were really helpful btw

phi
 one year ago
Best ResponseYou've already chosen the best response.1btw, we can treat 12 2*1 as 12+ 2*1 which gives 12+ 2 = 10 or as 12  2*1 wich is 12  2 = 10 the first way we think of adding 2 then second way , we think of it as subtracting

coming.home
 one year ago
Best ResponseYou've already chosen the best response.1Oooooo thanks for the tip :)
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