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anonymous

  • one year ago

???

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  1. IrishBoy123
    • one year ago
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    by linear approximation, do you mean \(V = \frac{4}{3} \pi r^3\), \(\Delta V = \frac{dV}{dr}\Delta r\) ?

  2. anonymous
    • one year ago
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    Would I derive the first one?

  3. welshfella
    • one year ago
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    yes differentiate (4/3) pi r^3 which is the formula for the volume of the sphere

  4. anonymous
    • one year ago
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    4pir^2

  5. welshfella
    • one year ago
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    correct

  6. anonymous
    • one year ago
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    And then what

  7. IrishBoy123
    • one year ago
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    then this https://gyazo.com/286b458598def9d5b57be9a7393d584f

  8. welshfella
    • one year ago
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    you know the value of r and delta r - Just plug them in and calculate

  9. anonymous
    • one year ago
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    36pi

  10. anonymous
    • one year ago
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    ?????

  11. IrishBoy123
    • one year ago
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    correct to within 0.01 inch in maths speak is: \(\Delta r = \pm 0.01\) you got \(\frac{dV}{dr} = 4 \pi r^2\) yourself, so finish the job

  12. welshfella
    • one year ago
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    36pi is correct for the value of 4 pi r^2 now you plug is the +/- 0.01

  13. welshfella
    • one year ago
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    * plug in

  14. anonymous
    • one year ago
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    .36

  15. welshfella
    • one year ago
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    no

  16. anonymous
    • one year ago
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    .036

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spraguer (Moderator)
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