anonymous
  • anonymous
the math club has 57 memebers who are in 6 or 7 grade there are twice as many 6 graders as 7 graders
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
welshfella
  • welshfella
I guess you need to find the number of 6th and 7th grades in the club right?
anonymous
  • anonymous
Let's substitute x for 7th graders.
anonymous
  • anonymous
|dw:1440317574984:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
We know that the total number of 6th-grade members and 7th-grade members is 57 members. So now we can write an equation.|dw:1440318115603:dw|
anonymous
  • anonymous
Finally, you can solve the equation by isolating x to get the number of 7th-grade members. After that, substitute the number of 7th-grade members for x in 2x to get the number of 6th-grade members.

Looking for something else?

Not the answer you are looking for? Search for more explanations.