## Lena772 one year ago A solution of aqueous Calcium hydroxide (1050.0 g) was formed by dissolving solid Calcium hydroxide in water (725 g). If the density of the solution is 1.45 g/mL, calculate the following:

1. Lena772

Mass Percent of Calcium hydroxide 59.2 parts per million of Calcium hydroxide 592000 molality 19.59 Molarity 19.59 Mole Fraction of Calcium hydroxide (Calculate this answer. Don't find it by subtracting the solvent's X from 1) 0.5915 Mole Fraction of Water (Calculate this answer. Don't find it by subtracting the solute's X from 1) 0.4366

2. Lena772

The answers I came up with are next to the problems, however they are incorrect.

3. Lena772

@welshfella

4. welshfella

i gotta go rihgt now sorry

5. Lena772

Alright.

6. Lena772

@mathmate @inkyvoyd @surjithayer @Luigi0210 @dan815

7. Lena772

8. mathmate

Are you sure the question said calcium hydroxide? The solubility of Ca(OH)2 is less than 0.2 g/100 ml in aqueous H2O, so it is impossible to have a density of 1.45g/mL. Do you mean 1050.0 g of Ca(OH)2 dissolved in 725 g of water, or 725 g of Ca(OH)2 dissolved in water to form 1050 g of solution? (It doesn't dissolve either way). It will not make a solution, but just a suspension (for whitewashing walls!) Perhaps NaOH or KOH would have that kind of solubility.

9. Lena772

That's exactly what the question said @mathmate. Do you see where I went wrong in my calculations?

10. Lena772

@Nnesha @zepdrix @Compassionate

11. Rushwr

first sort out the given data it says the aqueous solution was 1050g which means that 1050g has water and Ca(OH)2 both. And they have said mass of water in that is 725g Since they have asked for the mass percentage we have to calculate the mass of Ca(OH)2 in the solution that would be 1050-725 agree? So the mass of Ca(OJ)2 would be 325g Now calculate the mass percentage. $\frac{ 325 }{ 1050 }* 100% =30.95%$

12. Rushwr

the answer i got was 30.95 %

13. mathmate

@lena772 IMHO, the question went wrong, not you! lol