anonymous
  • anonymous
square ABCD has sides of length 12 units each. Points W, X, Y, and Z lie on sides AB, BC, CD, and DA, respectively, so that AW = 1/2 AB, BX = 1/2 BC, CY = 1/3 CD, and AZ = 1/4 DA. What is the area of the quadrilateral WXYZ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1440267886154:dw| I need your help
mathmate
  • mathmate
|dw:1440268312680:dw| Area of square, As= (12x)^2 = 144x^2 Calculate the total area of the 4 triangles at the four corners (A=bh/2) At=6x*6x+6x*4x+8x*9x+3x*6x=.... Subtract At from As to get the area of the quadrilateral. Aq=As-At
mathmate
  • mathmate
Correction: At=(6x*6x+6x*4x+8x*9x+3x*6x)/2=....

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anonymous
  • anonymous
????? I'm just in Junior high...
anonymous
  • anonymous
@mathmate
anonymous
  • anonymous
Did he answer the question??
anonymous
  • anonymous
IDK
mathmate
  • mathmate
If you are confused with the 12x and 144x^2 (which is a general case), set x=1, so the side of the square is 12 units (as given in the question.
mathmate
  • mathmate
|dw:1440269114269:dw|
mathmate
  • mathmate
Then calculate area of the four corner triangles: |dw:1440269166364:dw| The area of the square is 12*12=144 u^2 Area of the quadrilateral is 144-(sum of the areas of the four triangles). Can you take it from here?
anonymous
  • anonymous
So if each sides are 12. The area of the rectangle is 144. then add all of the triangles together subtract that from 144.

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