anonymous
  • anonymous
Came across this problem. I think the answer is 89. 1x6y7 is a 5 digit not divisible by 9. The number of ordered pair (x,y) satisfying this is?
Mathematics
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anonymous
  • anonymous
Came across this problem. I think the answer is 89. 1x6y7 is a 5 digit not divisible by 9. The number of ordered pair (x,y) satisfying this is?
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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mathmath333
  • mathmath333
i m getting 76
anonymous
  • anonymous
did you count from the complement and subtract from total?
mathmath333
  • mathmath333
might be wrong

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mathmath333
  • mathmath333
yep
anonymous
  • anonymous
total is 100 right?
mathmath333
  • mathmath333
wait
mathmath333
  • mathmath333
yes sry m getting 95
mathmath333
  • mathmath333
100-5
anonymous
  • anonymous
these are the pairs that I got that makes the number divisible by 9 (0,4), (1,3), (2,2), (3,1) , (4,0) (4, 9), (5,8), (6,7), (7,6), (8,5), (9,4)
anonymous
  • anonymous
I might under counted
mathmath333
  • mathmath333
ur answer looks right i didnt count the later x,y pairs
anonymous
  • anonymous
oh ok :)
mathmate
  • mathmate
@souwing @mathmath333 I have the same 11 ordered pairs that @souwing posted.

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