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A is correct
But is the given graph translated 4 units left? I thought a was right until I saw that
It would still have a v shape
I just need to know if I did a - e correctly. I believe c is correct. I am confused on what difference is a and b.
But is the graph translated 4 units left or not?
It's just it won't have to be on the y axis
The diference is that A's graph can be moved from left the right but B's graph moves up and down
They are still the same
Great, and is the given graph translated left, or is it at 0,0. Because I put all of my graphs at 0,0.
do I move the second graph 4 units up or 4 units down?
For B, u can move both up and down. For A u can move both left and right
Think of A as horizontal and think of B as vertical
I understand that, but do I move graph B up or down because the parent function is translated left. I left: up or down?
Wait, I think I got it. The graph is translated 2 units up, so I get it now
Is C correct? and is d and and e correct?
How do u upload image?
Use desmos and a screen shot. Or take a photo and use attach file. And you can also use the draw button.
Sry, on an Ipad
|dw:1440275742735:dw| I know it's a rough sketch. But is this an inverse? If yes, then C is correct. I believe D and E are wrong though
Yes c is correct. I'm investigating the equation of the graph
The graph looks like a sin graph but it has been dilated, translated, etc
The graph equation is 4sin(10/pi*x-2)-2
What should I do for D? Should I dilate it by 2?
And is graph E a compression?
Sry, I meant 4sin(5x/pi-2)-2
D makes the highest point 2 times taller and the lowest point 2 times lower maintaining the same center and shape
And E makes the farthest point to the right farther from the center and the farthest point to hit left 2 times farther. The domain becomes from -8 to 16 instead of -4 to.8
I'm not too sure about a and b
D and e are wrong tho.
Sry couldn't help as much
Anyone else with good help? Btw, thanks Plasmataco
Open a new one, please
Ok, will do.
I will include new graphs, (improved)