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anonymous
 one year ago
Am I doing these graphs correctly?
anonymous
 one year ago
Am I doing these graphs correctly?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But is the given graph translated 4 units left? I thought a was right until I saw that

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0It would still have a v shape

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just need to know if I did a  e correctly. I believe c is correct. I am confused on what difference is a and b.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But is the graph translated 4 units left or not?

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0It's just it won't have to be on the y axis

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0The diference is that A's graph can be moved from left the right but B's graph moves up and down

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0They are still the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Great, and is the given graph translated left, or is it at 0,0. Because I put all of my graphs at 0,0.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do I move the second graph 4 units up or 4 units down?

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0For B, u can move both up and down. For A u can move both left and right

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Think of A as horizontal and think of B as vertical

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand that, but do I move graph B up or down because the parent function is translated left. I left: up or down?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait, I think I got it. The graph is translated 2 units up, so I get it now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is C correct? and is d and and e correct?

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0How do u upload image?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Use desmos and a screen shot. Or take a photo and use attach file. And you can also use the draw button.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440275742735:dw I know it's a rough sketch. But is this an inverse? If yes, then C is correct. I believe D and E are wrong though

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Yes c is correct. I'm investigating the equation of the graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The graph looks like a sin graph but it has been dilated, translated, etc

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0The graph equation is 4sin(10/pi*x2)2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What should I do for D? Should I dilate it by 2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And is graph E a compression?

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Sry, I meant 4sin(5x/pi2)2

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0D makes the highest point 2 times taller and the lowest point 2 times lower maintaining the same center and shape

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0And E makes the farthest point to the right farther from the center and the farthest point to hit left 2 times farther. The domain becomes from 8 to 16 instead of 4 to.8

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0I'm not too sure about a and b

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0D and e are wrong tho.

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Sry couldn't help as much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Anyone else with good help? Btw, thanks Plasmataco

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Open a new one, please

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I will include new graphs, (improved)
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