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anonymous
 one year ago
Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
( 3,  25), and x intercepts at x = 8 and x = 2. (Do not include the negative sign in your answer.)
y = x2 + 6x − { Blank }
anonymous
 one year ago
Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of ( 3,  25), and x intercepts at x = 8 and x = 2. (Do not include the negative sign in your answer.) y = x2 + 6x − { Blank }

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@David27 Do you know how to do this?

David27
 one year ago
Best ResponseYou've already chosen the best response.0no sorry but he might know @ganeshie8

dan815
 one year ago
Best ResponseYou've already chosen the best response.1x intercept of 8 means the point (8,0) is a solution x int of 2 means the point (2,0) is a solution to your equation

dan815
 one year ago
Best ResponseYou've already chosen the best response.1y = x2 + 6x − { Blank } y = x2 + 6x −B knowing that (8,0) is a point of this parabola so, plugging that in for x,y 0=(8)^2+ 6*(8) B B=? solve for B you can also use the other point (2,0) 0=2^2+6*2B B=?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So solve 2^2+6*2 first?
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