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Question about your question, so I can choose any 4 values for a b c and d?

Are you sure there are 103 choose 3 positive integer solutions to a+b+c+d = 100 ?

ya with 0 included i think

do you find something wrong with that

can you explain what is wrong with that process

hmm wait are u sure 99 choose 3 is right htough

@SithsAndGiggles 99choose3 is right if 0 is not allowed

nice i really like that method

see if u can think about generalizations for this method like with
k1*a+K2*b+k3*c+d...+z=k