if sinx = 4/5 and x is in the first quadrant, find sin2x
What I know :
sin2x = 2sinxcosx (in my notes)
cos2x = 1-2sin^2x = -7/25 (I solved that myself)
sinx = 4/5 (given)

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Ok we now sin^2(x)+cos^2(x)=1 replace for sin(x) and find cos(x) then find sin(2x)

My notes are telling me to use the unit circle and to use the terminal point

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