if sinx = 4/5 and x is in the first quadrant, find sin2x What I know : sin2x = 2sinxcosx (in my notes) cos2x = 1-2sin^2x = -7/25 (I solved that myself) sinx = 4/5 (given)

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if sinx = 4/5 and x is in the first quadrant, find sin2x What I know : sin2x = 2sinxcosx (in my notes) cos2x = 1-2sin^2x = -7/25 (I solved that myself) sinx = 4/5 (given)

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Ok we now sin^2(x)+cos^2(x)=1 replace for sin(x) and find cos(x) then find sin(2x)
My notes are telling me to use the unit circle and to use the terminal point
Bro thats straight forward you got 16/25 +cos^2(x)=1 then cos^2(x)=9/25 then cos(x)=3/5 therfore sin(2x)=2(3/5)(4/5)=24/25 thats it i gave you the answer

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I'm a girl, not a "bro" and obviously it's not straight forward to me since I'm asking for help . I don't understand the terminal points and I'm taking an algebra 2 class and it's apparently trigonometry is apart of algebra 2
Sorry i had no idea what sex are you since your username didn't signify anything well yeah thats trig and it seems that you wrote in your notes everything that i just used what is the problem?
They're my initials and I don't understand how to find a terminal point . I don't understand trigonometry whatsoever
How old are you?
17
I don't see why my age is relevant lol
Nothing its just that I've taken trig form when i was 14 😂😜 im 17 now
If you want me I can explain trig to you but it would take time
how do you understand this
What trig?
yeah lol
By using scalar product in the trig circle
what's scalar product
Product of vectors, havent you heard of it?
no ..
Have you heard about the trig circle?
is that unit circle ?
?
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