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anonymous
 one year ago
How do you solve:
2/3= x+7/ 3x
anonymous
 one year ago
How do you solve: 2/3= x+7/ 3x

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0is it \[\frac{ x+7 }{ 3x } \rm ~or~x+\frac{ 7 }{ 3x }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0alright good \[\huge\rm \frac{ 2 }{ 3 }=\frac{ x+7 }{ 3x }\] cross multiply

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0here is an example \[\huge\rm \frac{ a }{ b }=\frac{ c }{ d}\]\[\rm ad=bc\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how @Amineh0923

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hint: 2/3 = x+7/3x 2(3x) = 3(x+7)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so was I right? its 6x / 3x+7 ? @twistnflip

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0eek, try again: 2/3 = x+7/3x 2(3x) = 3(x+7) You are missing one thing try one more time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there you go, awesome. Now do you know how to solve for x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think, I add 6x and 3x because they are like terms which leaves me with 9x = 21, then I divide each side by... oops that's not right :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep you are close though. instead (this is how i was taught) alway cosine terms by subtracting the smallest term from the biggest term. so here subtract 3x from 6x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so.. 6x= 3x + 21 3x 3x 3x= 21 /3 /3 x=7?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there you go!! awesome job

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks so much! I would fail this on the test if u hadn't cleared that up ;) :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no problem anything else? post a new question
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