anonymous
  • anonymous
How do you solve: 2/3= x+7/ 3x
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Nnesha
  • Nnesha
is it \[\frac{ x+7 }{ 3x } \rm ~or~x+\frac{ 7 }{ 3x }\]
anonymous
  • anonymous
the first one
Nnesha
  • Nnesha
alright good \[\huge\rm \frac{ 2 }{ 3 }=\frac{ x+7 }{ 3x }\] cross multiply

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Nnesha
  • Nnesha
here is an example \[\huge\rm \frac{ a }{ b }=\frac{ c }{ d}\]\[\rm ad=bc\]
anonymous
  • anonymous
Do you know how @Amineh0923
anonymous
  • anonymous
Hint: 2/3 = x+7/3x 2(3x) = 3(x+7)
anonymous
  • anonymous
Now distribute...
anonymous
  • anonymous
that's better ;)
anonymous
  • anonymous
so was I right? its 6x / 3x+7 ? @twistnflip
anonymous
  • anonymous
eek, try again: 2/3 = x+7/3x 2(3x) = 3(x+7) You are missing one thing try one more time
anonymous
  • anonymous
6x= 3x+21?
anonymous
  • anonymous
there you go, awesome. Now do you know how to solve for x?
anonymous
  • anonymous
I think, I add 6x and 3x because they are like terms which leaves me with 9x = 21, then I divide each side by... oops that's not right :(
anonymous
  • anonymous
yep you are close though. instead (this is how i was taught) alway cosine terms by subtracting the smallest term from the biggest term. so here subtract 3x from 6x
anonymous
  • anonymous
combine not cosine
anonymous
  • anonymous
so.. 6x= 3x + 21 -3x -3x 3x= 21 /3 /3 x=7?
anonymous
  • anonymous
there you go!! awesome job
anonymous
  • anonymous
thanks so much! I would fail this on the test if u hadn't cleared that up ;) :P
anonymous
  • anonymous
no problem anything else? post a new question

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