## anonymous one year ago How do you solve: 2/3= x+7/ 3x

1. Nnesha

is it $\frac{ x+7 }{ 3x } \rm ~or~x+\frac{ 7 }{ 3x }$

2. anonymous

the first one

3. Nnesha

alright good $\huge\rm \frac{ 2 }{ 3 }=\frac{ x+7 }{ 3x }$ cross multiply

4. Nnesha

here is an example $\huge\rm \frac{ a }{ b }=\frac{ c }{ d}$$\rm ad=bc$

5. anonymous

Do you know how @Amineh0923

6. anonymous

Hint: 2/3 = x+7/3x 2(3x) = 3(x+7)

7. anonymous

Now distribute...

8. anonymous

that's better ;)

9. anonymous

so was I right? its 6x / 3x+7 ? @twistnflip

10. anonymous

eek, try again: 2/3 = x+7/3x 2(3x) = 3(x+7) You are missing one thing try one more time

11. anonymous

6x= 3x+21?

12. anonymous

there you go, awesome. Now do you know how to solve for x?

13. anonymous

I think, I add 6x and 3x because they are like terms which leaves me with 9x = 21, then I divide each side by... oops that's not right :(

14. anonymous

yep you are close though. instead (this is how i was taught) alway cosine terms by subtracting the smallest term from the biggest term. so here subtract 3x from 6x

15. anonymous

combine not cosine

16. anonymous

so.. 6x= 3x + 21 -3x -3x 3x= 21 /3 /3 x=7?

17. anonymous

there you go!! awesome job

18. anonymous

thanks so much! I would fail this on the test if u hadn't cleared that up ;) :P

19. anonymous

no problem anything else? post a new question