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A. all negative values of f(x) become positive so the part of the graph below the x -axis is reflected in it.
Is A incorrect?
oh I'm taking the graph at the bottom to be the parent function
Oh I see now. So are A and B correct?
well yes - if f(x) is the curved function in your first post.
So what should I do with D and E?
I know they are not "v" graphs.
d is a stretch of the graph para;;;e; to the y-axis factor 2 |dw:1440283028819:dw|
the whole graph will be stretched ' up and down'
* parallel to y axis.
I got D, I will upload an image. please check it
yes thats right the point at y = 6 moves up to y = 12 - factor of 2
and should I make the period skinnier, or does it stay the same?
oh the minimum at y=-2 so only go down to -4
Oh, my bad I see that. and does the period (x) stay the same, or should i compress it?
well the whole thing will look skinnier i dont think they want you do draw it absolutely accurately - just a good sketch
But do the points stay the same for x?
for e it will stretch the graph horizontally with factor 2
if we take y = x^2 then 2 x^2 will look like as follows |dw:1440284048772:dw|
Oh, so there are two points for the graph. (-4,2) and (8,2). Do I keep them, or should I change them. And how if so?
oh sorry the x points do stay the same (-4,2) will become (-4,4) and ( 8,2) will move to (8,4)
So for D, they stay the same. And for E they become (-4,4) and (8,4)
its getting late in UK and i'm getting tired... lol
lol sorry bro, i'll give u a medal lol. Thank you
we're almost there. Just E, and that's it.
right e is a stretch parallel to x axis so x points will change y points will stay the same
Thank You got it!.
and the scale factor for e is 2