Find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y = 2.
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standard form: y = a(x-h)^2 + k
BTW did my help earlier help you?
yes quite a bit actually, sorry i didn't help so much I was a bit confused. but I will make it up to you now
lol kind of failed but you get the point. so the vertex is halfway between these points.
so the vertex is actually at (0,0)
in the standard from (h,k) is the vertex following so far?
Oh no its fine I understand!
y = a(x-h)^2 + k
y = a(x-0)^2 + 0
y = a(x)^2
a = 1/4c
c is 2, the difference between the focus and the vertex
so a = 1/(4*2)
a = 1/8
y = 1/8 (x)^2
Focus (0,-2) hence p=-2, right?
So just plug it in x^2=4py
hey my final answer is
y = 1/8(x)^2
Is that right?
awesome so do you get that @PHUNISH
Oh okay thanks guys1
But, to focus, direct fix oinformat6, you should apply the formula