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anonymous
 one year ago
help really stressed
A juggler is performing her act using several balls. She throws the balls up at an initial height of 4 feet, with a speed of 15 feet per second. If the juggler doesn't catch one of the balls, about how long does it take the ball to hit the floor?
Hint: Use H(t) = −16t2 + vt + s.
anonymous
 one year ago
help really stressed A juggler is performing her act using several balls. She throws the balls up at an initial height of 4 feet, with a speed of 15 feet per second. If the juggler doesn't catch one of the balls, about how long does it take the ball to hit the floor? Hint: Use H(t) = −16t2 + vt + s.

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Miracrown
 one year ago
Best ResponseYou've already chosen the best response.0\[h(t) = 16t^2 + vt + S\] We have an initial height of 4 feet in the equation, this is s ..we are also given a speed of 15 feet/second

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1I think the quadratic function will work for this

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1after plugging in everything

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.0in the equation, this is V and we are interested in the amount of time it iwll take for the ball to drop tot he ground at this time, height will be zero \[h(t)=−16t^2+vt+S \space = 0\]

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.0so what we have here is a quadratic equation, we can solve this using the quadratic formula like @Mehek14 said

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf{x=\dfrac{b±\sqrt{b^24ac}}{2a}}\)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1original formula is \(\bf{f(x)=ax^2+bx+c}\)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1for a, you have 16 for b, you have 15 and for c, you have 4 @jaredhm29 can you plug that into the quadratic formula?

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1@jaredhm29 are you there?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ive had a stuggle in this segment

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1can you plug a, b , and c into the quadratic formula?

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf{x=\dfrac{b±\sqrt{b^24ac}}{2a}}\)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1for a, you have 16 for b, you have 15 and for c, you have 4

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf{x=\dfrac{15±\sqrt{15^24*(16)*4}}{2*(16)}}\)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1first thing what is \(15^2=?\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please help me @Miracrown

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@zzr0ck3r @Miracrown

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0As @Miracrown said, \(\large h(t) = 16t^2 + vt + S\) is a standard kinematics equation giving the height h above datum (ground) at time t (therefore h(t)) as a function of t. v is the initial velocity (up = positive)=15 ft/s, and S= initial location (4 ft above datum= ground). 16 is actually acceleration due to gravity (32.2 ft/s^2) divided by 2, negative because acceleration is downwards. Substitute these values, you will get the same equation as @mehek14 showed you. Solving for t and reject the negative root gives you the time required.
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