help really stressed
A juggler is performing her act using several balls. She throws the balls up at an initial height of 4 feet, with a speed of 15 feet per second. If the juggler doesn't catch one of the balls, about how long does it take the ball to hit the floor?
Hint: Use H(t) = −16t2 + vt + s.
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please help me
\[h(t) = -16t^2 + vt + S\]
We have an initial height of 4 feet
in the equation, this is s ..we are also given a speed of 15 feet/second
As @Miracrown said,
\(\large h(t) = -16t^2 + vt + S\)
is a standard kinematics equation giving the height h above datum (ground) at time t (therefore h(t)) as a function of t.
v is the initial velocity (up = positive)=15 ft/s, and S= initial location (4 ft above datum= ground).
-16 is actually acceleration due to gravity (32.2 ft/s^2) divided by 2, negative because acceleration is downwards.
Substitute these values, you will get the same equation as @mehek14 showed you.
Solving for t and reject the negative root gives you the time required.