Someone please help with y=2^x?

- anonymous

Someone please help with y=2^x?

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- schrodinger

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- anonymous

Someone really really sweet helped me earlier today, but I dont think they are online.

- Mehek14

the table is linear
because the equation for it is
\(y=2x\)

- Mehek14

if you have the same ordered pairs as from the table

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## More answers

- Mehek14

so then yes
the table matches the graph

- Mehek14

and to find the 10th, just look at the y when x = 10

- anonymous

so wait this would be linear or exponential? I'm all confused again :/

- anonymous

okay wait the table when graphed is linear and then the equation I get using exponential regression, has to be - exponential?

- anonymous

Okay I found a website that does exponential regression using a table. & I think I have to do y=ab^x my numbers are a= 2.550657097 and b=1.259112119 are these right?

- anonymous

you don't need to do exponential regression for this because it's linear. The line of best fit is exactly
\[y=2x\]

- anonymous

I think I just thought it was expo because that's what the whole lessons about but yeah I mean it looks linear, but I still have to use expo regression (or constant ratio) to get an equation for this table and my rate of changes.

- anonymous

oh wait did you fill out that table or did they give it to you?

- anonymous

no I had to fill it in.

- anonymous

they gave me the first two and i did the rest

- anonymous

ok so each round DOUBLES
# of rounds | ppl receiving forward
1 2
2 4
3 8
4 16

- anonymous

That would make it exponential

- anonymous

oh dang really? I knew my table was wrong, but I didn't know exactly how.

- anonymous

okay well at least that is cleared up.

- anonymous

i'm going to redo this graph in google to see how it looks

- anonymous

ok. I think it should go smoothly from there

- anonymous

okay yeah it looks exponential now

- anonymous

ok

- anonymous

those rates of changes aren't going to be correct because the points changed

- anonymous

oh yeah sorry sorry I realized that as I posted them.

- anonymous

We did exponential earlier. Once you have the graph you can add the trendline

- anonymous

How did we get exponential? I remember just the equation being on the side there.

- anonymous

yeah you have to add the equation from the advanced options where you go to edit the chart

- anonymous

something like advanced edit I think

- anonymous

yeah that's it

- anonymous

okay so I have y=1e^(0.693x) how do I graph this over my original graph?

- anonymous

I think it graphs automatically

- anonymous

or I guess the line is just the same because I'm not seeing a new line just the one I had

- anonymous

yeah they'll be very close together for this one because you made up the points to match the function.
y = e^(0.693x) is basically the same as y = 2^x

- anonymous

okay yeah when I did advanced edit and all that stuff, the dot graph I had just changed to the plots being connected with a line, so I guess that they overlay eachother?

- anonymous

yeah that sounds right

- anonymous

how do I figure that out? Something with the 10th round?

- anonymous

@peachpi

- anonymous

my connection is so bad rn I don't know if I'm seeing replies

- anonymous

your equation is y = 2^x
50000 = 2^x
Solve for x

- anonymous

15?

- anonymous

yes

- anonymous

awesome! Again I appreciate your help so much. Can't thank you enough <3

- anonymous

you're welcome

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