anonymous
  • anonymous
Someone please help with y=2^x?
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Someone really really sweet helped me earlier today, but I dont think they are online.
Mehek14
  • Mehek14
the table is linear because the equation for it is \(y=2x\)
Mehek14
  • Mehek14
if you have the same ordered pairs as from the table

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Mehek14
  • Mehek14
so then yes the table matches the graph
Mehek14
  • Mehek14
and to find the 10th, just look at the y when x = 10
anonymous
  • anonymous
so wait this would be linear or exponential? I'm all confused again :/
anonymous
  • anonymous
okay wait the table when graphed is linear and then the equation I get using exponential regression, has to be - exponential?
anonymous
  • anonymous
Okay I found a website that does exponential regression using a table. & I think I have to do y=ab^x my numbers are a= 2.550657097 and b=1.259112119 are these right?
anonymous
  • anonymous
you don't need to do exponential regression for this because it's linear. The line of best fit is exactly \[y=2x\]
anonymous
  • anonymous
I think I just thought it was expo because that's what the whole lessons about but yeah I mean it looks linear, but I still have to use expo regression (or constant ratio) to get an equation for this table and my rate of changes.
anonymous
  • anonymous
oh wait did you fill out that table or did they give it to you?
anonymous
  • anonymous
no I had to fill it in.
anonymous
  • anonymous
they gave me the first two and i did the rest
anonymous
  • anonymous
ok so each round DOUBLES # of rounds | ppl receiving forward 1 2 2 4 3 8 4 16
anonymous
  • anonymous
That would make it exponential
anonymous
  • anonymous
oh dang really? I knew my table was wrong, but I didn't know exactly how.
anonymous
  • anonymous
okay well at least that is cleared up.
anonymous
  • anonymous
i'm going to redo this graph in google to see how it looks
anonymous
  • anonymous
ok. I think it should go smoothly from there
anonymous
  • anonymous
okay yeah it looks exponential now
anonymous
  • anonymous
ok
anonymous
  • anonymous
those rates of changes aren't going to be correct because the points changed
anonymous
  • anonymous
oh yeah sorry sorry I realized that as I posted them.
anonymous
  • anonymous
We did exponential earlier. Once you have the graph you can add the trendline
anonymous
  • anonymous
How did we get exponential? I remember just the equation being on the side there.
anonymous
  • anonymous
yeah you have to add the equation from the advanced options where you go to edit the chart
anonymous
  • anonymous
something like advanced edit I think
anonymous
  • anonymous
yeah that's it
anonymous
  • anonymous
okay so I have y=1e^(0.693x) how do I graph this over my original graph?
anonymous
  • anonymous
I think it graphs automatically
anonymous
  • anonymous
or I guess the line is just the same because I'm not seeing a new line just the one I had
anonymous
  • anonymous
yeah they'll be very close together for this one because you made up the points to match the function. y = e^(0.693x) is basically the same as y = 2^x
anonymous
  • anonymous
okay yeah when I did advanced edit and all that stuff, the dot graph I had just changed to the plots being connected with a line, so I guess that they overlay eachother?
anonymous
  • anonymous
yeah that sounds right
anonymous
  • anonymous
how do I figure that out? Something with the 10th round?
anonymous
  • anonymous
anonymous
  • anonymous
my connection is so bad rn I don't know if I'm seeing replies
anonymous
  • anonymous
your equation is y = 2^x 50000 = 2^x Solve for x
anonymous
  • anonymous
15?
anonymous
  • anonymous
yes
anonymous
  • anonymous
awesome! Again I appreciate your help so much. Can't thank you enough <3
anonymous
  • anonymous
you're welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.