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anonymous

  • one year ago

Someone please help with y=2^x?

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  1. anonymous
    • one year ago
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    Someone really really sweet helped me earlier today, but I dont think they are online.

  2. Mehek14
    • one year ago
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    the table is linear because the equation for it is \(y=2x\)

  3. Mehek14
    • one year ago
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    if you have the same ordered pairs as from the table

  4. Mehek14
    • one year ago
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    so then yes the table matches the graph

  5. Mehek14
    • one year ago
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    and to find the 10th, just look at the y when x = 10

  6. anonymous
    • one year ago
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    so wait this would be linear or exponential? I'm all confused again :/

  7. anonymous
    • one year ago
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    okay wait the table when graphed is linear and then the equation I get using exponential regression, has to be - exponential?

  8. anonymous
    • one year ago
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    Okay I found a website that does exponential regression using a table. & I think I have to do y=ab^x my numbers are a= 2.550657097 and b=1.259112119 are these right?

  9. anonymous
    • one year ago
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    you don't need to do exponential regression for this because it's linear. The line of best fit is exactly \[y=2x\]

  10. anonymous
    • one year ago
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    I think I just thought it was expo because that's what the whole lessons about but yeah I mean it looks linear, but I still have to use expo regression (or constant ratio) to get an equation for this table and my rate of changes.

  11. anonymous
    • one year ago
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    oh wait did you fill out that table or did they give it to you?

  12. anonymous
    • one year ago
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    no I had to fill it in.

  13. anonymous
    • one year ago
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    they gave me the first two and i did the rest

  14. anonymous
    • one year ago
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    ok so each round DOUBLES # of rounds | ppl receiving forward 1 2 2 4 3 8 4 16

  15. anonymous
    • one year ago
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    That would make it exponential

  16. anonymous
    • one year ago
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    oh dang really? I knew my table was wrong, but I didn't know exactly how.

  17. anonymous
    • one year ago
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    okay well at least that is cleared up.

  18. anonymous
    • one year ago
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    i'm going to redo this graph in google to see how it looks

  19. anonymous
    • one year ago
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    ok. I think it should go smoothly from there

  20. anonymous
    • one year ago
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    okay yeah it looks exponential now

  21. anonymous
    • one year ago
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    ok

  22. anonymous
    • one year ago
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    those rates of changes aren't going to be correct because the points changed

  23. anonymous
    • one year ago
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    oh yeah sorry sorry I realized that as I posted them.

  24. anonymous
    • one year ago
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    We did exponential earlier. Once you have the graph you can add the trendline

  25. anonymous
    • one year ago
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    How did we get exponential? I remember just the equation being on the side there.

  26. anonymous
    • one year ago
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    yeah you have to add the equation from the advanced options where you go to edit the chart

  27. anonymous
    • one year ago
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    something like advanced edit I think

  28. anonymous
    • one year ago
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    yeah that's it

  29. anonymous
    • one year ago
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    okay so I have y=1e^(0.693x) how do I graph this over my original graph?

  30. anonymous
    • one year ago
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    I think it graphs automatically

  31. anonymous
    • one year ago
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    or I guess the line is just the same because I'm not seeing a new line just the one I had

  32. anonymous
    • one year ago
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    yeah they'll be very close together for this one because you made up the points to match the function. y = e^(0.693x) is basically the same as y = 2^x

  33. anonymous
    • one year ago
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    okay yeah when I did advanced edit and all that stuff, the dot graph I had just changed to the plots being connected with a line, so I guess that they overlay eachother?

  34. anonymous
    • one year ago
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    yeah that sounds right

  35. anonymous
    • one year ago
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    how do I figure that out? Something with the 10th round?

  36. anonymous
    • one year ago
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    @peachpi

  37. anonymous
    • one year ago
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    my connection is so bad rn I don't know if I'm seeing replies

  38. anonymous
    • one year ago
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    your equation is y = 2^x 50000 = 2^x Solve for x

  39. anonymous
    • one year ago
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    15?

  40. anonymous
    • one year ago
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    yes

  41. anonymous
    • one year ago
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    awesome! Again I appreciate your help so much. Can't thank you enough <3

  42. anonymous
    • one year ago
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    you're welcome

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