Annie96
  • Annie96
The set {0,1} is closed under which operation? none of the above addition multiplication subtraction
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
A set has closure if you can do that operation in any direction and always get a number that belongs to that set.
jim_thompson5910
  • jim_thompson5910
A set is closed under an operation if you can take any 2 numbers in the set, perform the operation on them, and have the result be a number in the set For example: {1, 2, 3} this set is NOT closed under addition because 2+3 = 5. The numbers 2 and 3 are in the set, but 5 is not.
anonymous
  • anonymous
lol nice

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anonymous
  • anonymous
So for this one: 0+1 = 1 But also 0 * 1 = 0 So... it should be multiplication and addition, but thats not a choice. @jim_thompson5910 thoughts?
jim_thompson5910
  • jim_thompson5910
addition won't work because 1+1 = 2 is not in the set
jim_thompson5910
  • jim_thompson5910
same idea for subtraction
anonymous
  • anonymous
oh ok, sorry I didn't think that way. so its going to be multiplication
jim_thompson5910
  • jim_thompson5910
yes 0*0 = 0 0*1 = 0 1*0 = 0 1*1 = 1 a table is usually a good way to sort it all out |dw:1440287363879:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1440287420902:dw|
anonymous
  • anonymous
ok thanks for helping out
jim_thompson5910
  • jim_thompson5910
no problem
zzr0ck3r
  • zzr0ck3r
a weird way to ask a question.... operations are closed by definition.
zzr0ck3r
  • zzr0ck3r
an operation \(\circ\) on \(X\) is a function \(\circ:X\times X\rightarrow X\)

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