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Annie96

  • one year ago

The set {0,1} is closed under which operation? none of the above addition multiplication subtraction

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  1. anonymous
    • one year ago
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    A set has closure if you can do that operation in any direction and always get a number that belongs to that set.

  2. jim_thompson5910
    • one year ago
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    A set is closed under an operation if you can take any 2 numbers in the set, perform the operation on them, and have the result be a number in the set For example: {1, 2, 3} this set is NOT closed under addition because 2+3 = 5. The numbers 2 and 3 are in the set, but 5 is not.

  3. anonymous
    • one year ago
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    lol nice

  4. anonymous
    • one year ago
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    So for this one: 0+1 = 1 But also 0 * 1 = 0 So... it should be multiplication and addition, but thats not a choice. @jim_thompson5910 thoughts?

  5. jim_thompson5910
    • one year ago
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    addition won't work because 1+1 = 2 is not in the set

  6. jim_thompson5910
    • one year ago
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    same idea for subtraction

  7. anonymous
    • one year ago
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    oh ok, sorry I didn't think that way. so its going to be multiplication

  8. jim_thompson5910
    • one year ago
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    yes 0*0 = 0 0*1 = 0 1*0 = 0 1*1 = 1 a table is usually a good way to sort it all out |dw:1440287363879:dw|

  9. jim_thompson5910
    • one year ago
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    |dw:1440287420902:dw|

  10. anonymous
    • one year ago
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    ok thanks for helping out

  11. jim_thompson5910
    • one year ago
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    no problem

  12. zzr0ck3r
    • one year ago
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    a weird way to ask a question.... operations are closed by definition.

  13. zzr0ck3r
    • one year ago
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    an operation \(\circ\) on \(X\) is a function \(\circ:X\times X\rightarrow X\)

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