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anonymous

  • one year ago

(1/9)l5x-3l -3 ≥ 2 (Those l's are for absolute value. I am so confused. Anyone got a solution?)

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  1. mathmate
    • one year ago
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    Solve separately the expression |5x-3| as +(5x-3) and -(5x-3), which means you have two solutions. solve (1/9)(5x-3)\(\ge\)2 and -(1/9)(5x-3)\(\ge\)2 to get the two required solutions.

  2. anonymous
    • one year ago
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    I have to solve for x and I think I have to start with l5x-3l - 3 = 18

  3. mathmate
    • one year ago
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    Yes, that's ok too!, now put the expression as 5x-3 and -(5x-3) and solve the equations.

  4. mathmate
    • one year ago
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    but (1/9)(5x-3)-3≥2 => (5x-3)-27≥18 and -(1/9)(5x-3)-3≥2 => -(5x-3)-27≥18

  5. anonymous
    • one year ago
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    ummm

  6. mathmate
    • one year ago
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    Add 27 to both sides, we have (5x-3)-27+27≥18+27 -(5x-3)-27+27≥18+27 or 5x-3≥45 and -5x+3≥45 solve accordingly.

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