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anonymous

  • one year ago

help here

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  1. anonymous
    • one year ago
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    yes

  2. anonymous
    • one year ago
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    Let X be a topological space, Let \[{x_{n}} \] be a sequence of elements in X. Then\[ x_{n} \] is said to converge to x\[\epsilon \] X if \[\forall \] nbds U of x, there exists N\[\epsilon \] N such that \[\forall \] n\[\geslant \] N, \[x_{n} \]\[\epsilon \] U

  3. anonymous
    • one year ago
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    then one of these conditions does not hold

  4. anonymous
    • one year ago
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    A) \[x_{n} \rightarrow x , as.. n\rightarrow N \]

  5. anonymous
    • one year ago
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    ya this is not in my range of knowledge, that looks like 20 years of college

  6. zzr0ck3r
    • one year ago
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    The option you showed is true.

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spraguer (Moderator)
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