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anonymous
 one year ago
help here
anonymous
 one year ago
help here

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let X be a topological space, Let \[{x_{n}} \] be a sequence of elements in X. Then\[ x_{n} \] is said to converge to x\[\epsilon \] X if \[\forall \] nbds U of x, there exists N\[\epsilon \] N such that \[\forall \] n\[\geslant \] N, \[x_{n} \]\[\epsilon \] U

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then one of these conditions does not hold

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A) \[x_{n} \rightarrow x , as.. n\rightarrow N \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ya this is not in my range of knowledge, that looks like 20 years of college

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0The option you showed is true.
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