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anonymous

  • one year ago

the question is "y= -2x + 1" and it needs to be graphed. Do I divied -2x by -2? Also does that make the y intercept 1? Im just checking my answer :)

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  1. anonymous
    • one year ago
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    the x intercept is certainly 1, because \((0,1)\) is on the graph

  2. anonymous
    • one year ago
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    and no, you do not divide by anything pick an x, find the y, plot the point for example, if \(x=2\) then \(y=-2\times 2+1=-3\) so \((2,-3)\) is on the graph

  3. anonymous
    • one year ago
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    so can you walk me through the problem how it should be done so I know for next time?

  4. anonymous
    • one year ago
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    i thought i just did, but we can go slower if you like you know the y intercept is 1, because you said it, so \((0,1)\) is on the graph |dw:1440292521307:dw|

  5. anonymous
    • one year ago
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    now the slope is \(-2\) which means for every increase of 1 in x, the y values decreases by 2

  6. anonymous
    • one year ago
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    Oh, so do I just plot -2 on the x-axis?

  7. anonymous
    • one year ago
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    but we can do ahead and plot a few points then connect the dots

  8. anonymous
    • one year ago
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    no you do not

  9. anonymous
    • one year ago
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    lets put \(x=1\) and see what \(y\) is

  10. anonymous
    • one year ago
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    if \(x=1\) then \(y=-2\times 1+1=-2+1=-1\) so the point \((1,-1)\) is on the graph

  11. anonymous
    • one year ago
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    |dw:1440292666244:dw|

  12. anonymous
    • one year ago
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    maybe now pick \(x=2\) then if \(x=2\) you have \[y=-2\times 2+1=-4+1=-3\] so now we know \((2,-3)\) is on the graph

  13. anonymous
    • one year ago
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    |dw:1440292749283:dw|

  14. anonymous
    • one year ago
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    once you have a few points plotted, they should line up nicely and you connect the dots to get your line

  15. anonymous
    • one year ago
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    |dw:1440292799179:dw|

  16. anonymous
    • one year ago
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    ok thanks :)

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