Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y = –2x^2 +6x – 1. A) x = 3; vertex: (3, 35) B) x = –1.5; vertex: (–1.5, – 14.5) C) x = –1.5; vertex: (–1.5, –5.5) D) x = 1.5; vertex: (1.5, 3.5)

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Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y = –2x^2 +6x – 1. A) x = 3; vertex: (3, 35) B) x = –1.5; vertex: (–1.5, – 14.5) C) x = –1.5; vertex: (–1.5, –5.5) D) x = 1.5; vertex: (1.5, 3.5)

Mathematics
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@Jhannybean Your up
completing the square again ? just for variety, maybe look at the graph, does it look symmetric about any line ? |dw:1440293427749:dw|
First you're going to want to complete the square in order to put your quadratic function in vertex form.

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Mwuahaha @ganeshie8 is tired of this.
lol not really, just saying it for effect haha!
:P But what is the scaling value of your axes? you didnt label anything there haha
Just a lazier way to find the vertex, \[x=- \frac{ b }{ 2a }\] just throwing that out there.
good point, it is confusing w/o labeling and stuff yeah

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