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anonymous
 one year ago
Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y = –2x^2 +6x – 1.
A) x = 3; vertex: (3, 35)
B) x = –1.5; vertex: (–1.5, – 14.5)
C) x = –1.5; vertex: (–1.5, –5.5)
D) x = 1.5; vertex: (1.5, 3.5)
anonymous
 one year ago
Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y = –2x^2 +6x – 1. A) x = 3; vertex: (3, 35) B) x = –1.5; vertex: (–1.5, – 14.5) C) x = –1.5; vertex: (–1.5, –5.5) D) x = 1.5; vertex: (1.5, 3.5)

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0completing the square again ? just for variety, maybe look at the graph, does it look symmetric about any line ? dw:1440293427749:dw

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1First you're going to want to complete the square in order to put your quadratic function in vertex form.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1Mwuahaha @ganeshie8 is tired of this.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0lol not really, just saying it for effect haha!

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1:P But what is the scaling value of your axes? you didnt label anything there haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just a lazier way to find the vertex, \[x= \frac{ b }{ 2a }\] just throwing that out there.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0good point, it is confusing w/o labeling and stuff yeah
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