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anonymous

  • one year ago

how do I find the y and x intercepts? "y= -2x +1"

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  1. Jhannybean
    • one year ago
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    just use the replace and solve method. Replace y with 0, solve for x. : x intercept. Replace x with 0, solve for y : y-intercept

  2. anonymous
    • one year ago
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    let me try it

  3. anonymous
    • one year ago
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    y= -2x +1 0= -2x + 1 -1 -1 -1 = -2x

  4. anonymous
    • one year ago
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    The problem is I don't know what to do once I am at this part...

  5. Jhannybean
    • one year ago
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    in order to isolate x, we have to divide both sides by -2

  6. jim_thompson5910
    • one year ago
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    agreed with Jhannybean -2x means "-2 times x" so if we had -2x = -1, and we wanted to isolate x, we undo the multiplication of the -2 the opposite of multiplication is division. You must divide both sides by -2 to isolate x

  7. anonymous
    • one year ago
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    You first have to divide -2x by both sides so you would end up with y= x + -2

  8. anonymous
    • one year ago
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    so x + 0.5?

  9. jim_thompson5910
    • one year ago
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    I think you meant `x = 0.5` ?

  10. anonymous
    • one year ago
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    oops I mean x = 0.5

  11. jim_thompson5910
    • one year ago
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    correct. That or x = 1/2 which is the same thing in different form

  12. anonymous
    • one year ago
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    thanks

  13. jim_thompson5910
    • one year ago
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    @Jhannybean why do that? You stated above that y = 0. That's what led to x = 0.5 Don't you mean plug in x = 0 ?

  14. anonymous
    • one year ago
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    so I plot one on (0.5,0) and another on (0,1) ?

  15. Jhannybean
    • one year ago
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    That's true...i thought you could do either or. inputting it into my calculator i realize that it isn't possible.

  16. anonymous
    • one year ago
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    was what I put correct?

  17. jim_thompson5910
    • one year ago
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    `so I plot one on (0.5,0) and another on (0,1) ?` correct @Amineh0923 now draw a straight line through those points

  18. anonymous
    • one year ago
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    |dw:1440294750279:dw|

  19. anonymous
    • one year ago
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    @jim_thompson5910 thanks

  20. jim_thompson5910
    • one year ago
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    no problem

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