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AmTran_Bus

  • one year ago

Integrate

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  1. AmTran_Bus
    • one year ago
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    |dw:1440294714804:dw|

  2. anonymous
    • one year ago
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    In this case, would you be considering pi as 3.14?

  3. AmTran_Bus
    • one year ago
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    well duh

  4. anonymous
    • one year ago
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    Your answer would round up to 6 then

  5. AmTran_Bus
    • one year ago
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    @ganeshie8 @Hero @Jhannybean @inkyvoyd

  6. Jhannybean
    • one year ago
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    Just to clarify one small thing, \(d\phi\) or \(d\theta\)?

  7. AmTran_Bus
    • one year ago
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    The first :)

  8. Jhannybean
    • one year ago
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    \[\frac{1}{\sqrt{2\pi}} \int d\phi\]\[=\frac{\phi}{\sqrt{2\pi}}+c\]?? Hahaha. Idk it feels liek theres more to it.

  9. Jhannybean
    • one year ago
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    like*

  10. AmTran_Bus
    • one year ago
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    Yea, I agree. How do you integrate the bottom?

  11. Jhannybean
    • one year ago
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    What bottom are you referring to?

  12. AmTran_Bus
    • one year ago
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    sqrt 2pi

  13. AmTran_Bus
    • one year ago
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    OHH nvm I see

  14. Jhannybean
    • one year ago
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    \[\frac{1}{\sqrt{2\pi}}\] this is a constant, therefore can be extracted from the integral before even integrating. Right?

  15. AmTran_Bus
    • one year ago
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    Got it. My bad. Thanks.

  16. Jhannybean
    • one year ago
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    No problemo

  17. Empty
    • one year ago
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    This reminds me of a problem that always tricks people, "What's the derivative of \(\pi^2\)" and everyone likes to say \(2 \pi\) instead of 0 haha

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