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arindameducationusc
 one year ago
Different Lift Cases in NLM=>
(Tutorial)
arindameducationusc
 one year ago
Different Lift Cases in NLM=> (Tutorial)

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arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.10\(\Huge\color{Blue}{Different~Lift~Cases} \)

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.10in Newtons Laws of motion

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.10Case 1=> Consider a lift which is moving upward with acceleration 'a' and a person is standing on the floor of lift. The person standing on the floor of lift is under the influence of two forces 1)Normal reaction due to flor of lift 2)Weight(mg) due to Earth dw:1440296184019:dw Net upward force on man= Nmg Now, Nmg=ma Because \[F _{net}=ma\] so, N=mg+ma \[N=m(g+a)\]

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.10If a platform balance is placed on the floor of lift and man is allowed to stand over it then the force exerted by man on balance will be mg+ma (in case 1), which is greater than the true weight of the man,i.e, mg

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.10Case 2> If a lift is moving downward with acceleration a. dw:1440296743979:dw Therefore downward force on man mgN Therefore, mgN=ma \[N=m(ga) \] Apparent weight<True Weight (here)

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.10Case 3=> If cable of lift breaks then a=g putting in above equation N=m(ga) we get N=0 In case of free falling of lift, man is in the condition of weightlessness .

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.10Case 4=> If a>g in downward direction In this case man is also in free falling,i.e, lift and man both are coming downward wrt observer standing on the ground dw:1440297484077:dw Now if a>g then lift is moving faster with acceleration 'a' but you are in free fall with acceleration 'g'. This makes the lift go faster downward, eventually I collide with the top of the lift. dw:1440298160222:dw Now when head of mine (man) collided with ceiling of lift N+mg=ma \[N=mamg\]

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.10Hope this helps. Happy learning.... :) Enyone can share their knowledge here....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.10Thank you @rvc

shreehari499
 one year ago
Best ResponseYou've already chosen the best response.0Good job! Easily understandable :)

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.10Thank you @shreehari499
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