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tywower

  • one year ago

Below is a Maxwell-Boltzman distribution curve graph. Which statement offers the best interpretation of the graph?

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  1. tywower
    • one year ago
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  2. tywower
    • one year ago
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    Curve 1 is at a higher temperature than curve 2. Curve 1 has a higher activation energy than curve 2. Curve 2 is at a higher temperature than curve 1. Curve 2 has a catalyst added to the reaction.

  3. tywower
    • one year ago
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    @pooja195

  4. tywower
    • one year ago
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    @aaronq

  5. tywower
    • one year ago
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    hiiii @arindameducationusc !! can u help me with this? i have no ideas

  6. arindameducationusc
    • one year ago
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    haven't tried problems like this for a long time... But there is a 60% chance I can help you, but can you give me some time?

  7. tywower
    • one year ago
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    sure!

  8. arindameducationusc
    • one year ago
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    Effect of Temperature on distribution of speeds=> It may be noted that the fraction of molecules having the most probable speed remains same as long as temperature remains same. However on increasing the temperature of the gas the molecular motion becomes rapid and consequently the value of the most probable speed also increases. The entire distribution curve, in fact shifts towards right with rise in temperature (Will show you in figure). How ever the area under the two curves remains same because it represents number of molecules. |dw:1440299572636:dw|

  9. arindameducationusc
    • one year ago
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    I hope it helped @tywower So, you guess what could be the answer?

  10. tywower
    • one year ago
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    not sure

  11. tywower
    • one year ago
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    im thinking a or b

  12. arindameducationusc
    • one year ago
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    Please read my paragraph....

  13. arindameducationusc
    • one year ago
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    The graph shifts towards right so....

  14. tywower
    • one year ago
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    c?

  15. arindameducationusc
    • one year ago
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    YES! GOOD JOB

  16. tywower
    • one year ago
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    :)

  17. arindameducationusc
    • one year ago
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    Did you like my response?

  18. Abhisar
    • one year ago
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    |dw:1440304703087:dw|

  19. Abhisar
    • one year ago
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    On increasing temperature, fraction of molecules having energy greater than activation energy increases. In the diagram we can see that fraction of molecule having energy greater that \(\sf E_a\) is larger at temperature \(\sf T_2\). So we can conclude that \(\sf T_2 > T_1\)

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