tywower
  • tywower
Below is a Maxwell-Boltzman distribution curve graph. Which statement offers the best interpretation of the graph?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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tywower
  • tywower
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tywower
  • tywower
Curve 1 is at a higher temperature than curve 2. Curve 1 has a higher activation energy than curve 2. Curve 2 is at a higher temperature than curve 1. Curve 2 has a catalyst added to the reaction.
tywower
  • tywower
@pooja195

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tywower
  • tywower
@aaronq
tywower
  • tywower
hiiii @arindameducationusc !! can u help me with this? i have no ideas
arindameducationusc
  • arindameducationusc
haven't tried problems like this for a long time... But there is a 60% chance I can help you, but can you give me some time?
tywower
  • tywower
sure!
arindameducationusc
  • arindameducationusc
Effect of Temperature on distribution of speeds=> It may be noted that the fraction of molecules having the most probable speed remains same as long as temperature remains same. However on increasing the temperature of the gas the molecular motion becomes rapid and consequently the value of the most probable speed also increases. The entire distribution curve, in fact shifts towards right with rise in temperature (Will show you in figure). How ever the area under the two curves remains same because it represents number of molecules. |dw:1440299572636:dw|
arindameducationusc
  • arindameducationusc
I hope it helped @tywower So, you guess what could be the answer?
tywower
  • tywower
not sure
tywower
  • tywower
im thinking a or b
arindameducationusc
  • arindameducationusc
Please read my paragraph....
arindameducationusc
  • arindameducationusc
The graph shifts towards right so....
tywower
  • tywower
c?
arindameducationusc
  • arindameducationusc
YES! GOOD JOB
tywower
  • tywower
:)
arindameducationusc
  • arindameducationusc
Did you like my response?
Abhisar
  • Abhisar
|dw:1440304703087:dw|
Abhisar
  • Abhisar
On increasing temperature, fraction of molecules having energy greater than activation energy increases. In the diagram we can see that fraction of molecule having energy greater that \(\sf E_a\) is larger at temperature \(\sf T_2\). So we can conclude that \(\sf T_2 > T_1\)

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