8(2x – 14) + 13 = 4x – 27 i know x=6 but i need a step by step way how to get it

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8(2x – 14) + 13 = 4x – 27 i know x=6 but i need a step by step way how to get it

Mathematics
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I would distribute where possible 8(2x-14)=? recall a(b+c)=a*b+a*c
16x-112
so then we have: \[16x-112+13=4x-27\]

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now we do have like terms on the left hand side
-112+13=?
-99
that is what I have too... \[16x-99=4x-27\]
now we need to get the terms with x on one side and the terms without x on the opposing side
-4x?
right subtract 4x on both sides
16x-4x-99=4x-4x-27 this will make x go away on one side since 4x-4x=0 12x-99=-27
you mean +99 on both side sright?
haha yea
\[12x-99+99=-27+99\] yes this would isolate the 12x on the left hand side since -99+99=0 \[12x=-27+99\]
so we do have like terms on the right hand side -27+99=?
combine like terms
-27+99=72 so we have: \[12x=72 \text{ since } 99-27=72\] last step is to...
we want to isolate the x but x is being multiplied by 12
so divide both sides by?
12
\[12x=72 \\ \frac{12x}{12}=\frac{72}{12} \\ \frac{12}{12}x=\frac{72}{12} \\ 1 x=\frac{72}{12} \text{ since } \frac{12}{12}=1 \\ x=\frac{72}{12} \text{ since } 1x=x\]
thanks so much
you just have to reduce 72/12 and you are done (aka divide)
np

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