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anonymous

  • one year ago

Decide how many solutions this equation has: x^2 + 3 = 0

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  1. anonymous
    • one year ago
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    @twistnflip

  2. ganeshie8
    • one year ago
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    may be just try solving it : \(x^2+3=0 \implies x^2=-3 \implies \cdots \)

  3. anonymous
    • one year ago
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    Okay can you explain to me how to solve it. I came uo with x=6 so one solution but i dont know if thats correct

  4. ganeshie8
    • one year ago
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    plugin \(x=6\) does it make the given equation true ?

  5. anonymous
    • one year ago
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    I think not

  6. ganeshie8
    • one year ago
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    x^2 + 3 = 0 6^2 + 3 = 0 36 + 3 = 0 39 = 0 which is clearly false, so nope, x=6 is not a solution.

  7. anonymous
    • one year ago
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    What about a square root of negative 3? Does such thing exist?

  8. anonymous
    • one year ago
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    I think there is no solution right?

  9. anonymous
    • one year ago
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    What if I try putting the negative sign before the bracket surrounding square root of 3?

  10. anonymous
    • one year ago
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    Like -(sqrt(3)) Probably I am wrong.

  11. anonymous
    • one year ago
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    Nah forget it I don't think that even exists.

  12. anonymous
    • one year ago
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    So yeah, I think x would have to be of square root value but with the negative sign I think that makes the equation unsolvable. Is that correct?

  13. freckles
    • one year ago
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    depends on the set we are solving over but no sqrt(-3) doesn't equal -sqrt(3) sqrt(-3) is imaginary while -sqrt(3) is real

  14. anonymous
    • one year ago
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    Right. Imaginary root shuold be used as the solution. So I belive minus square root of three might be more relevant? Forgive me if I am wrong.

  15. freckles
    • one year ago
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    \[(-\sqrt{3})^2=((-1)\sqrt{3})^2= (-1)^2 (\sqrt{3})^2=1(3)=3 \neq -3\]

  16. anonymous
    • one year ago
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    So that's the full solution for x apparently. @abriannaridley I guess that's your take home message from todayXD

  17. anonymous
    • one year ago
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    lol thanks for everyones help! :P

  18. freckles
    • one year ago
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    what conclusion did you draw from this @abriannaridley ?

  19. ganeshie8
    • one year ago
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    im liking jokes that cortana tells me when i feel bored... so let me tell you a joke :) gimme one moment to type..

  20. anonymous
    • one year ago
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    okay so im not 100% if this is right but there is only solution to that problem? @freckles

  21. freckles
    • one year ago
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    only solution you mean no real solution right?

  22. freckles
    • one year ago
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    x^2=negative number will never happen under the real numbers

  23. anonymous
    • one year ago
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    Does cortana make no comment like Siri when you talk like a you know person ?

  24. anonymous
    • one year ago
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    Yes lol! should've just said no solution

  25. freckles
    • one year ago
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    x^2=negative number can happen under the complex numbers

  26. anonymous
    • one year ago
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    Find the x-intercepts of the graph of the equation: y = x2 - 3x + 2 im not sure how to do this one either should i just post it as a new question?

  27. freckles
    • one year ago
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    x-intercepts can found by setting y to 0 and solve for x

  28. anonymous
    • one year ago
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    ohh okay!

  29. freckles
    • one year ago
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    and yeah to prevent things from getting to long sometimes it is best to post a new question

  30. freckles
    • one year ago
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    but you can post a question I guess if you have trouble solving 0=x^2-3x+2

  31. ganeshie8
    • one year ago
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    sry for the delay, here it is : ``` A foreman is yelling down into an excavation : "How many of you men down there ?" the reply came back, "three." and he said "Okay, half of you come on up." ```

  32. freckles
    • one year ago
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    but you can post a question I guess if you have trouble solving 0=x^2-3x+2

  33. ganeshie8
    • one year ago
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    that joke refers to solving the equation \(2x=3\). does it really have a solution ? If it has a solution, what does it represent ?

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