anonymous
  • anonymous
8x2 + 64x = 0
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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e.mccormick
  • e.mccormick
I am guessling that is 8x^2... So, what problem are you having with it?
anonymous
  • anonymous
the answers choices are x=0 ,x=-8 x=0,x=8 x=-8,x=0,x=8 x=8,x=64
anonymous
  • anonymous
@e.mccormick

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e.mccormick
  • e.mccormick
Yes, and what is giving your trouble? This is a tutoring site...
anonymous
  • anonymous
i dont understand anything at all im lost can you explain ?
e.mccormick
  • e.mccormick
When you have something = 0 equations, you need to factor it and then find when the factors would be 0. This is sometimes called the roots, zeros, or x intercepts of a polynomial.
e.mccormick
  • e.mccormick
So, if you factor \(8x^2 + 64x\), what do you get?
anonymous
  • anonymous
8x^2
e.mccormick
  • e.mccormick
Um, that is the first term, but it is not the factors.
anonymous
  • anonymous
ok , so can you break this down in help me step by step ?
e.mccormick
  • e.mccormick
Well, do you know what factoring is?
anonymous
  • anonymous
not a clue
e.mccormick
  • e.mccormick
OK, if I say \(a\times b\times c\) then a, b and c are factors. They are multiplied together. Another common use is prime factorization. Like how 15 has the prime factors of 3 and 5. So that polynomeal is the result of multiplying together something. When you un-multiply it, you are factoring it.
anonymous
  • anonymous
x^2 would be the factors ?
e.mccormick
  • e.mccormick
No, it would be something like \((x\pm h)(x\pm k)\) where h and k are some constants.
e.mccormick
  • e.mccormick
If I multiply out \((x+1)(x-3)\) I get: \(x^2+x-3x-3\) or: \(x^2-2x-3\) So \((x+1)\) and \((x-3)\) are factors of \(x^2-2x-3\). That is why factoring can be called un-multiplying.
anonymous
  • anonymous
ion know i just guessed
e.mccormick
  • e.mccormick
One big clue with this one is that each term has x in it. If you factor out the x, what would you get?
zzr0ck3r
  • zzr0ck3r
when someone is helping you, and they ask you a question and you guess, it makes them not want to hep you.
anonymous
  • anonymous
solve your equation step-by-step. 8x2+64x=0 Factor left side of equation. 8x(x+8)=0 Set factors equal to 0. 8x=0 or x+8=0 This should be more than enough clues :)

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