elp plez!!!

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why am i getting -14.3m at the maximum height??????????

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as*
please upload nicely. 2.3 what???
m/sec
that's the initial launch velocity....2.3m/sec
hmmm
use H=u^2sin^2theta/2g where u=2.3 g=9.8 and theta = 78
nope i wasa still getting some negative answer -_-
2.3^2=5.29 sin78=0.51 (use calculator) 5.29*(0.51)^2/2*9.8 =1.37/19.6
why didn't you squared the sin?
|dw:1440300973805:dw|
I squared (I skipped one step) Please see carefully
and why isn't gravity = -9.8m/Sec^2 here???? O_o :) :D
No no its \[H=\frac{ u ^{2}\sin ^{2}\theta }{ 2g }\]
so 9.8 as g?
why are you taking -9.8 ? g=9.8 We take minus because of direction sometimes!
yes yes 9.8 =g
cuz when an object goes up, the gravity is always -9.8....
but when the object goes down, then it's 9.8...
not necessary. The direction totally depends on you... and ya H will always be +ve because of height
ok let me calculate this now.....
ok
|dw:1440301420914:dw|
yes
Good
|dw:1440301591574:dw|
does that make any sense, cuz something that launches at 2.4m/s at an angle of 78deg has a maximum altitude of 0.24m??????
sorry 2.3m/sec
yes yes good
see the highest Maximum height is for angle 45 degrees, 78 will go very low
angle 60 and angle 30 go same maximum height angle 78 and angle 12 go same max height
yes i understand that...any degree higher than 45 will increase the vertical displacement of the object while decreasing the horizontal displacement.....
cuz after the 45 angle, the vertical comp starts to increase while the hori comp starts to decrease...
but styll 0.24m seems small..but i guess it's ok....
yup
hey can you check one more question...i've already done it, just check it real quick!!!
okay will try, dont forget to medal and fan @YumYum247

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