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YumYum247

  • one year ago

elp plez!!!

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  1. YumYum247
    • one year ago
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  2. YumYum247
    • one year ago
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    @arindameducationusc

  3. YumYum247
    • one year ago
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    why am i getting -14.3m at the maximum height??????????

  4. YumYum247
    • one year ago
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    as*

  5. arindameducationusc
    • one year ago
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    please upload nicely. 2.3 what???

  6. YumYum247
    • one year ago
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    m/sec

  7. YumYum247
    • one year ago
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    that's the initial launch velocity....2.3m/sec

  8. arindameducationusc
    • one year ago
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    hmmm

  9. arindameducationusc
    • one year ago
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    use H=u^2sin^2theta/2g where u=2.3 g=9.8 and theta = 78

  10. YumYum247
    • one year ago
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    nope i wasa still getting some negative answer -_-

  11. arindameducationusc
    • one year ago
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    2.3^2=5.29 sin78=0.51 (use calculator) 5.29*(0.51)^2/2*9.8 =1.37/19.6

  12. YumYum247
    • one year ago
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    why didn't you squared the sin?

  13. YumYum247
    • one year ago
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    |dw:1440300973805:dw|

  14. arindameducationusc
    • one year ago
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    I squared (I skipped one step) Please see carefully

  15. YumYum247
    • one year ago
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    and why isn't gravity = -9.8m/Sec^2 here???? O_o :) :D

  16. arindameducationusc
    • one year ago
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    No no its \[H=\frac{ u ^{2}\sin ^{2}\theta }{ 2g }\]

  17. YumYum247
    • one year ago
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    so 9.8 as g?

  18. arindameducationusc
    • one year ago
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    why are you taking -9.8 ? g=9.8 We take minus because of direction sometimes!

  19. arindameducationusc
    • one year ago
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    yes yes 9.8 =g

  20. YumYum247
    • one year ago
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    cuz when an object goes up, the gravity is always -9.8....

  21. YumYum247
    • one year ago
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    but when the object goes down, then it's 9.8...

  22. arindameducationusc
    • one year ago
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    not necessary. The direction totally depends on you... and ya H will always be +ve because of height

  23. YumYum247
    • one year ago
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    ok let me calculate this now.....

  24. arindameducationusc
    • one year ago
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    ok

  25. YumYum247
    • one year ago
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    |dw:1440301420914:dw|

  26. arindameducationusc
    • one year ago
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    yes

  27. arindameducationusc
    • one year ago
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    Good

  28. YumYum247
    • one year ago
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    |dw:1440301591574:dw|

  29. YumYum247
    • one year ago
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    does that make any sense, cuz something that launches at 2.4m/s at an angle of 78deg has a maximum altitude of 0.24m??????

  30. YumYum247
    • one year ago
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    sorry 2.3m/sec

  31. arindameducationusc
    • one year ago
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    yes yes good

  32. arindameducationusc
    • one year ago
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    see the highest Maximum height is for angle 45 degrees, 78 will go very low

  33. arindameducationusc
    • one year ago
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    angle 60 and angle 30 go same maximum height angle 78 and angle 12 go same max height

  34. YumYum247
    • one year ago
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    yes i understand that...any degree higher than 45 will increase the vertical displacement of the object while decreasing the horizontal displacement.....

  35. YumYum247
    • one year ago
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    cuz after the 45 angle, the vertical comp starts to increase while the hori comp starts to decrease...

  36. YumYum247
    • one year ago
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    but styll 0.24m seems small..but i guess it's ok....

  37. arindameducationusc
    • one year ago
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    yup

  38. YumYum247
    • one year ago
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    hey can you check one more question...i've already done it, just check it real quick!!!

  39. arindameducationusc
    • one year ago
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    okay will try, dont forget to medal and fan @YumYum247

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