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YumYum247
 one year ago
elp plez!!!
YumYum247
 one year ago
elp plez!!!

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YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0@arindameducationusc

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0why am i getting 14.3m at the maximum height??????????

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1please upload nicely. 2.3 what???

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0that's the initial launch velocity....2.3m/sec

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1use H=u^2sin^2theta/2g where u=2.3 g=9.8 and theta = 78

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0nope i wasa still getting some negative answer _

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.12.3^2=5.29 sin78=0.51 (use calculator) 5.29*(0.51)^2/2*9.8 =1.37/19.6

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0why didn't you squared the sin?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440300973805:dw

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1I squared (I skipped one step) Please see carefully

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0and why isn't gravity = 9.8m/Sec^2 here???? O_o :) :D

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1No no its \[H=\frac{ u ^{2}\sin ^{2}\theta }{ 2g }\]

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1why are you taking 9.8 ? g=9.8 We take minus because of direction sometimes!

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1yes yes 9.8 =g

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0cuz when an object goes up, the gravity is always 9.8....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0but when the object goes down, then it's 9.8...

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1not necessary. The direction totally depends on you... and ya H will always be +ve because of height

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok let me calculate this now.....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440301420914:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440301591574:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0does that make any sense, cuz something that launches at 2.4m/s at an angle of 78deg has a maximum altitude of 0.24m??????

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1yes yes good

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1see the highest Maximum height is for angle 45 degrees, 78 will go very low

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1angle 60 and angle 30 go same maximum height angle 78 and angle 12 go same max height

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0yes i understand that...any degree higher than 45 will increase the vertical displacement of the object while decreasing the horizontal displacement.....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0cuz after the 45 angle, the vertical comp starts to increase while the hori comp starts to decrease...

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0but styll 0.24m seems small..but i guess it's ok....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0hey can you check one more question...i've already done it, just check it real quick!!!

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1okay will try, dont forget to medal and fan @YumYum247
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