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anonymous

  • one year ago

Find the x-intercepts of the graph of the equation: y = x^2 - 3x + 2 hmm so i got x=2, and x=1 which doesn't make sense

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  1. ganeshie8
    • one year ago
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    why ?

  2. anonymous
    • one year ago
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    well when i plugged the numbers in it wasn't equivalent

  3. freckles
    • one year ago
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    \[2^2-3(2)+2=0 ? \\ \text{ well } 2^2-3(2)+2=4-6+2=-2+2=0 \\ \text{ so } 2^2-3(2)+2=0 \text{ is a true equation }\]

  4. freckles
    • one year ago
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    and you can check the other one in a similar way

  5. freckles
    • one year ago
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    you should get \[1^2-3(1)+2 \text{ is also } 0\]

  6. anonymous
    • one year ago
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    oh wait so i got it right....

  7. freckles
    • one year ago
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    yes the x-intercepts are (2,0) and (1,0)

  8. freckles
    • one year ago
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    you solved 0=x^2-3x+2 correctly

  9. anonymous
    • one year ago
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    OMG!!!! proud moment :P

  10. freckles
    • one year ago
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    you did good! :)

  11. anonymous
    • one year ago
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    thanks! :)

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