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anonymous
 one year ago
How would you use the trigonometric subtraction formula to verify this identity:
anonymous
 one year ago
How would you use the trigonometric subtraction formula to verify this identity:

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sin(\frac{ \pi }{ 2 }x)=cosx\]

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1\(\sin(\alpha\beta)= \sin(\alpha)\cos(\beta)\sin(\beta)\cos(\alpha)\) Using that we have \(\sin(\dfrac{\pi}{2}x)=\sin(\dfrac{\pi}{2})\cos(x)\sin(x)\cos(\dfrac{\pi}{2})=1*\cos(x)\sin(x)*0=\cos(x)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you explain to me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0=1∗cos(x)−sin(x)∗0=cos(x)

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1They said you can use this formula \[\sin(\alpha\beta)= \sin(\alpha)\cos(\beta)\sin(\beta)\cos(\alpha)\] If we let \(\alpha=\dfrac{\pi}{2}\) and let \(\beta=x\) we get the above result.

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1well what is 1*cos(x)? what is 0*sin(x)? what is cos(x) 0?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah , but why did you add that part ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Like why is that part there

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1http://openstudy.com/study#/updates/55d94ce2e4b05a670c276053

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1I feel like there is an echo in here.
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