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anonymous

  • one year ago

How would you use the trigonometric subtraction formula to verify this identity:

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  1. anonymous
    • one year ago
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    \[\sin(\frac{ \pi }{ 2 }-x)=cosx\]

  2. zzr0ck3r
    • one year ago
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    \(\sin(\alpha-\beta)= \sin(\alpha)\cos(\beta)-\sin(\beta)\cos(\alpha)\) Using that we have \(\sin(\dfrac{\pi}{2}-x)=\sin(\dfrac{\pi}{2})\cos(x)-\sin(x)\cos(\dfrac{\pi}{2})=1*\cos(x)-\sin(x)*0=\cos(x)\)

  3. anonymous
    • one year ago
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    Can you explain to me

  4. zzr0ck3r
    • one year ago
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    which part?

  5. anonymous
    • one year ago
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    =1∗cos(x)−sin(x)∗0=cos(x)

  6. zzr0ck3r
    • one year ago
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    They said you can use this formula \[\sin(\alpha-\beta)= \sin(\alpha)\cos(\beta)-\sin(\beta)\cos(\alpha)\] If we let \(\alpha=\dfrac{\pi}{2}\) and let \(\beta=x\) we get the above result.

  7. zzr0ck3r
    • one year ago
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    well what is 1*cos(x)? what is 0*sin(x)? what is cos(x) -0?

  8. anonymous
    • one year ago
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    Yeah , but why did you add that part ?

  9. zzr0ck3r
    • one year ago
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    add?

  10. anonymous
    • one year ago
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    Like why is that part there

  11. UnkleRhaukus
    • one year ago
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    http://openstudy.com/study#/updates/55d94ce2e4b05a670c276053

  12. zzr0ck3r
    • one year ago
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    I feel like there is an echo in here.

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spraguer (Moderator)
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