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anonymous
 one year ago
Combination Problem
anonymous
 one year ago
Combination Problem

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The starting 5 in a basketball team is to be picked, in order, from the 10 playes in the squad. In how many ways can this be done if Jamahl and Anfernee must be in the starting 5. Remember this is a permutation question.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2so you need to choose 3 other players from the remaining 8 this can be done in \(\dbinom{8}{3}\) ways

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2after that, you can permute the \(5\) member team : " Jamahl, Anfernee and the other \(3\) players" in \(5!\) ways

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2so there are \(\dbinom{8}{3}*5!\) ways to make the team

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What do you mean by permuting 5 people in 5 ways @ganeshie8?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2"permute" refers to a rearrangement for example : \((b,a,c,d,e)\) is a permutation of \((a,b,c,d,e)\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2after choosing 5 member for the team, you need to rank them in order right ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0AHH, I see what you mean. Thank you!
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