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Ahsome

  • one year ago

Combination Problem

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  1. ahsome
    • one year ago
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    The starting 5 in a basketball team is to be picked, in order, from the 10 playes in the squad. In how many ways can this be done if Jamahl and Anfernee must be in the starting 5. Remember this is a permutation question.

  2. ganeshie8
    • one year ago
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    so you need to choose 3 other players from the remaining 8 this can be done in \(\dbinom{8}{3}\) ways

  3. ganeshie8
    • one year ago
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    after that, you can permute the \(5\) member team : " Jamahl, Anfernee and the other \(3\) players" in \(5!\) ways

  4. ganeshie8
    • one year ago
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    so there are \(\dbinom{8}{3}*5!\) ways to make the team

  5. ahsome
    • one year ago
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    What do you mean by permuting 5 people in 5 ways @ganeshie8?

  6. ganeshie8
    • one year ago
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    "permute" refers to a rearrangement for example : \((b,a,c,d,e)\) is a permutation of \((a,b,c,d,e)\)

  7. ganeshie8
    • one year ago
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    after choosing 5 member for the team, you need to rank them in order right ?

  8. ahsome
    • one year ago
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    AHH, I see what you mean. Thank you!

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