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anonymous
 one year ago
ques
anonymous
 one year ago
ques

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\vec \nabla \times \vec \nabla \times \vec f=\vec \nabla(\vec \nabla . \vec f)\nabla^2 \vec f\] Can we use vector triple product to prove this identity??Expanding it is long and unecessary :/

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1are you familiar with the Ricci's symbol

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1you can apply this identity: \[\Large {\mathbf{a}} \times \left( {{\mathbf{b}} \times {\mathbf{c}}} \right) = \left( {{\mathbf{a}} \cdot {\mathbf{c}}} \right){\mathbf{b}}  \left( {{\mathbf{a}} \cdot {\mathbf{b}}} \right){\mathbf{c}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's what I am asking if it's ok to use that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It looks like a quick and cheat method lol

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! you have to memorize that identity :)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0do it!! you're just pattern matching after all and \(\nabla\) is functionally a vector....
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