A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

ques

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\vec \nabla \times \vec \nabla \times \vec f=\vec \nabla(\vec \nabla . \vec f)-\nabla^2 \vec f\] Can we use vector triple product to prove this identity??Expanding it is long and unecessary :/

  2. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    are you familiar with the Ricci's symbol

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Nope

  4. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you can apply this identity: \[\Large {\mathbf{a}} \times \left( {{\mathbf{b}} \times {\mathbf{c}}} \right) = \left( {{\mathbf{a}} \cdot {\mathbf{c}}} \right){\mathbf{b}} - \left( {{\mathbf{a}} \cdot {\mathbf{b}}} \right){\mathbf{c}}\]

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that's what I am asking if it's ok to use that

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It looks like a quick and cheat method lol

  7. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes! you have to memorize that identity :)

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    alright sweet :D

  9. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    :)

  10. IrishBoy123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    do it!! you're just pattern matching after all and \(\nabla\) is functionally a vector....

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah :P

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.