anonymous
  • anonymous
The data set gives the number of bottles filled by each of the workers in a bottling plant in one day. {36, 18, 16, 28, 68, 35, 37, 66, 38, 40, 41, 44, 72, 29} The best measure of center for this data set is the , and its value expressed up to one decimal place is
Mathematics
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anonymous
  • anonymous
The data set gives the number of bottles filled by each of the workers in a bottling plant in one day. {36, 18, 16, 28, 68, 35, 37, 66, 38, 40, 41, 44, 72, 29} The best measure of center for this data set is the , and its value expressed up to one decimal place is
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
The best would be the median
anonymous
  • anonymous
how do I find the value?
welshfella
  • welshfella
arrange the values in ascending order the median is the middle number (if the total number is odd) or he mean of the 2 middle numbers.

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anonymous
  • anonymous
@welshfella I know that part
anonymous
  • anonymous
I need to know the value
welshfella
  • welshfella
i've just explained how to get it.
welshfella
  • welshfella
there are 2 parts to the question 1. what is the best measure of center 2. what is the value of this best measure.
welshfella
  • welshfella
OK?
anonymous
  • anonymous
order these numbers; {36, 18, 16, 28, 68, 35, 37, 66, 38, 40, 41, 44, 72, 29} , then find the middle number of the order
IrishBoy123
  • IrishBoy123
out of interest, why the median and not the mean? https://gyazo.com/adeb20b7894f04112ea381c640e00bba is this really that skewed?
anonymous
  • anonymous
mean is affected by outliers
IrishBoy123
  • IrishBoy123
yes it is, but the trendline suggests that there aren't really any outliers. i reason that the go-to measure of central tendency is the arithmetic mean. now, if you work total output as 14 times mean for this sample vs 14 times median, you get very different results. in fact you are out by nearly 10% if you use median. this is not a massively skewed distribution. skewness \(\frac{\mu - \nu}{\sigma} = 0.18\). not totally sure how to interpret that, but it certainly isn't a big number.
IrishBoy123
  • IrishBoy123
i'm just wondering why the median was selected as best without any analysis, and the whole thread's focus is on how you calc a median. if you take the outlier argument too seriously, you never get to use the arithmetic mean unless every data point is exactly the same :p
welshfella
  • welshfella
you have a valid point there @irishboy. I guess this is a 'borderline' case.
IrishBoy123
  • IrishBoy123
thanks @welshfella ! i can see it both ways, i just wonder is it really about judgement or is there a test? i do see those 3 higher numbers but they are 3 in a set of 14. if it was just one, i might see it differently.
welshfella
  • welshfella
yes I agree about the outliers I wonder if people lean towards the median if the amount of data is small because its easier to calculate!?

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