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anonymous
 one year ago
How many moles of carbon dioxide gas can be produced when 12.8 moles of benzene (C6H6) react with excess oxygen? I balanced the equation as 2C6H6 + 15O2 > 12CO2 + 6H2O but I am stuck again
anonymous
 one year ago
How many moles of carbon dioxide gas can be produced when 12.8 moles of benzene (C6H6) react with excess oxygen? I balanced the equation as 2C6H6 + 15O2 > 12CO2 + 6H2O but I am stuck again

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Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2yeah the equation is balanced perfectly ! Where do u get stuck

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont understand how I find the amount of moles like do i take the 12.8 and divide it by the molar mass?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.21) we know the no. of moles of benzene right? 12.8mol 2) See the mole ratio between benzene and co2 ! That is 2:12 if we simplify it more 1:6 right ?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2That is 2 moles of benzene froms 12 moles of CO2 . Or we can say 1 moles of benzene forms 6 moles of CO2 ! Got it up to this point ?

JFraser
 one year ago
Best ResponseYou've already chosen the best response.0when you balance a chemical equation, you're not just balancing individual atoms, you're also creating a \(mole\) ratio between the components, as @rushwr is saying

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohhhh okay now I completely understand that but what is the next step

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2Now we know the moles of benzene that 12.8 mol So we can find the no. of moles of CO2 right ? We know 1mole of benzene forms 6moles of CO2 right? So to find the no. of moles of CO2 formed by 12.8 moles of benzene we have to multiply 12.8 from 6 and this amount would be the no. of moles of CO2 ! Right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be 76.8 right? and that would be CO2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait it was that easy?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0Good job @Rushwr

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2Thanx @arindameducationusc :)
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