A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
How many grams of magnesium oxide can be produced when 97.2 g Mg react with 88.5 g O2? I balanced the equation as 2Mg + O2 > 2MgO but I have now gotten two different answers
anonymous
 one year ago
How many grams of magnesium oxide can be produced when 97.2 g Mg react with 88.5 g O2? I balanced the equation as 2Mg + O2 > 2MgO but I have now gotten two different answers

This Question is Open

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I took the 97.2 g Mg and divided by the molar mass of 24.3050 g/mol and got 3.999 mol Mg But since the ratio is 1:1 I don't understand what to do now

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Hey! This is also easy. 1st find the moles of each compound separately. O2 moles = 88.5g divided by 32gmol^1 = 2.766mol Mg moles = 97.2g divided by 24.3050gmol^1 = 3.999mol According to that Mg to O2 ratio is 2:1 right? but looking at the no. of moles of each we can say that the ratio isn't correct right? But we know the reaction will occur in that ratio anyhow ! According to the equation O2 moles needed to react with 3.99 moles of Mg is 1.995 moles. But we have 2.766 moles right? That means we have ecess oxygen. Also means Mg is the limiting factor of the reaction. Amount of Mg limits the reaction. So we have to use the no. of moles of Mg cuz it's the limiting factor. Okai ? As we can see in the equation the ratio of Mg used to MgO produced is 2:2 so it will have the same no. of moles. Hope you can do the rest of it alone ! Did u get it ? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think I did I kinda got a bit lost

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Where did u get it confused ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do I use the second ratio like I understand why I have to use them but how?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1It's like this 1st we have to identify the limiting agent. 2nd ratio luk at the equation. The ratio of both moles of Mg used up to MgO formed is 1:1 right ?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1that means if u use x moles of Mg x moles of MgO will be formed !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes and so I multiply 3.999 mol x 3.999 mol?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1no no u don't have to multiply so we just get that idea that the moles of Mg used is equal to the no. of moles of MgO formed right? Since we have asked to workout the grams of MgO use n=m/M nno. of moles mmass Mmolar mass So we know the no. of moles and molar mass, WE have to find the mass. Substitute the values u will get the mass

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So 1.383 + 3.999 g 5.382 / 40.3044 g/mol

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1why did u add ? u have to multiply the no of moles and the molar mass

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0to get the number of moles the O2 i divided 2.766 by 2 and got 1.383 and added that to Mg 3.999 I am assuming i am wrong

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1it's like this Since we are given with the masses of both the reactants we have to find the moles of each reactant. We find it to see if there's any limiting agent. Ex: think we are finding the moles of Mg and O2 after that the ratio of moles were 2:1 exactly there's no limiting agent. But here we found that we don't get that ratio right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes oh wait so I do it for each one?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1for each reactants separately ! We found that earlier In my 1st comment that is given !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhhhh thats my fault okay let me try this again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03.999/24.3050 = .1645 2.766/31.9988 = 11.5686 like this?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Hey I think U need more help with this!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its okay if you can't explain it to me ill get it eventually

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1reply me ! I messaged u !
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.