anonymous
  • anonymous
At Priscilla's Purse Warehouse, it takes 2/3 of a day to complete 1/9 of an order of purses. At this rate, how long will it take to complete the entire order of purses?
Mathematics
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anonymous
  • anonymous
At Priscilla's Purse Warehouse, it takes 2/3 of a day to complete 1/9 of an order of purses. At this rate, how long will it take to complete the entire order of purses?
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Hero
  • Hero
Hint: (1/9)*9 = 1 order of purses
anonymous
  • anonymous
thx
Hero
  • Hero
@Maxipoo124, did you figure how how long it will take to complete the entire order?

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anonymous
  • anonymous
yes
Hero
  • Hero
How long will it take?
anonymous
  • anonymous
13 1/2 days
Hero
  • Hero
What calculations did you use to come up with that result?
anonymous
  • anonymous
2/3 x 9 cross multiplied
Hero
  • Hero
There's no cross multiplying involved in calculating (2/3)*9 ,
anonymous
  • anonymous
well i multiplied 3 x 9 and divided it by 2 and got 13.5 but into a fraction its 13 1/2
Hero
  • Hero
You only cross multiply if you have a proportion: \[\dfrac{a}{b} = \dfrac{c}{d}\] \[ad = bc\]
Hero
  • Hero
This is what you're multiplying: \[\dfrac{2}{3} \times \dfrac{9}{1}\] You multiply the numerators first. Then the denominators
anonymous
  • anonymous
so six days
Hero
  • Hero
Yes, correct.
anonymous
  • anonymous
thank you so much for the help

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