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mathmath333
 one year ago
Counting question
mathmath333
 one year ago
Counting question

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{Their are 4 apples, 5 mangoes and 6 watermelons .}\hspace{.33em}\\~\\ & \normalsize \text{Find the number of ways }\hspace{.33em}\\~\\ & \normalsize \text{i.) I can purchase at least each of them. }\hspace{.33em}\\~\\ & \normalsize \text{ii.) I can purchase at least one of them. }\hspace{.33em}\\~\\ \end{align}}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3notice that apples have 5 states : {0, 1, 2, 3, 4} mangoes have 6 states : {0, 1, 2, 3, 4, 5} watermelons have 7 states : {0, 1, 2, 3, 4, 5, 6}

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0is this correct =(2^41)*(2^51)*(2^61)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the english is a bit unclear to me " I can purchase at least each of them"

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0but it is given 4*5*6 ways

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats the answer for part a) ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3for partb, is the answer 5*6*7  1 ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3it seems textbook is treating all the fruit types as indistinguishable @jayzdd

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes , hmm i guess i treated them as distinguishable

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0all apples are are identical and so all mango

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the apple choice you can pick 1 apple 2 apples 3 apples 4 apples a total of 4 ways to select the apples Then multiply this by the number of selections you can make for mango 1 mango 2 mangoes 3 mangoes 4 mongoes 5 mangoes a total of 5 choices and then similarly for the watermelon there are 6 ways to select them by multiplication principle, 4*5*6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for part b) now include the zero case

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the apple choice you can pick 0 apples, 1 apple, 2 apples, 3 apples , 4 apples a total of 5 ways to select the apples Then multiply this by the number of selections you can make for mango 0 mango 1 mango 2 mangoes 3 mangoes 4 mangoes 5 mangoes a total of 6 ways to select And then similarly for the watermelon 0 watermelon, 1 watermelon, ... 6 watermelon there are 7 ways to select them By multiplication principle, 5*6*7 But the directions say at least one fruit, so we cannot have 0 apple and 0 mangoe, and 0 watermelon. so we subtract 1

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0like these method in the previuos question there were 5 methods for bulb so how can i judge distinguishable bulbs or fruits

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The bulbs were fixed by the socket, so there was an ordering to them. lightbulb 1, lightbulb2, ... lightbulb 5 Here there is no natural order to the fruits, since they are indistinguishable. If they want to treat the fruits as distinguishable, the directions would explicitly say it. otherwise assume indistinguishable

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440349712575:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the sockets are distinguishable i would say , and there are 2 states for each socket (on or off)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440349885112:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If the lightbulbs had no sockets, then the lightbulbs would be indistinguishable. But then there would be no light either. Since lightbulbs had light, we could assume they were connected to distinguishable sockets, and cannot move. This forces an ordering to the lightbulbs that make them distinguishable.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The lightbulbs connected to the sockets are fixed in space and bolted down, because they are constructed that way by the carpenter. But the apples and mangoe fruits are not bolted down, so what matters is how many you pick, not which one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Think of it this way. When you select the fruits, imagine you are blindfolded. There are three bags, a bag for apples , a bag for mangoes, bag for watermelons. You are instructed to select as many fruits from each bag as you want. The apples are all the same (let's imagine for the sake of argument). The mangoes are all exactly the same and the watermelons the same. you can select 0 apples, 1 apple, 2 apples... up to 4 apples. you can select 0 mangoes up to 5 mangoes, etc Doing this blindfold experiment would not make sense for the lighbulb example.
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