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anonymous
 one year ago
Logarithm question
anonymous
 one year ago
Logarithm question

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[7\ln \left \frac{ x+\sqrt{x^{2}  7} }{ \sqrt{7} } \right = 7(\ln \left x+\sqrt{x ^{2}7} \right \ln \sqrt{7} \]

yamyam70
 one year ago
Best ResponseYou've already chosen the best response.0are we asked to prove?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0you're missing a bracket and call that numerator inside the log something like "A" and rewrite it again. it might look way less foreboding

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.0\[\log a^x = x \log a~~~~ and ~~~~ \log a  \log b = \log \frac{ a }{ b }\]

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0hey lnx= ln x i mean u can remove it

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0proofdw:1440351441869:dw

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1In any case, the following is an identity, use the standard identities given by @rishavraj to prove the followin: \(\large 7\ln \left \frac{ x+\sqrt{x^{2}  7} }{ \sqrt{7} } \right = 7(\ln \left x+\sqrt{x ^{2}7} \right \ln \sqrt{7})\)

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@mathmate @IrishBoy123 my prove i draw it right ;p

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2lnx and ln x do not have the same domain, therefore they are not the same
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