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- anonymous

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- schrodinger

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- anonymous

- Vocaloid

well, first start by factoring the numerator

- anonymous

|dw:1440350088787:dw|
Thats what it looks like

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## More answers

- anonymous

im not sure how to factor the top

- anonymous

x(x-3...?

- freckles

you know @jcoury you don't have to do all that work

- anonymous

?

- freckles

all the x values are different in the choices
just find when the bottom is zero

- anonymous

yeah but that is -4 but look at the answer choices

- freckles

there is only one choice with x as -4

- freckles

you don't need to find y

- anonymous

D?

- anonymous

??

- freckles

yep that is the only choice that has x as -4

- freckles

however

- freckles

if you want to find the y-coordinate you can factor the top and cancel out the common factor of (x+4) after so then plug in x as -4 to find the corresponding y value is -11

- anonymous

kk

- anonymous

thx

- anonymous

that us ut

- anonymous

it^

- freckles

it might be good practice to do so

- anonymous

k

- anonymous

can u help with one more @freckles

- freckles

k

- anonymous

What is the discontinuity and zero of the function f(x) = the quantity of 2 x squared plus 5 x minus 12, all over x plus 4?

- anonymous

Discontinuity at (−4, −11), zero at (three halves , 0)
Discontinuity at (−4, −11), zero at (negative three halves , 0)
Discontinuity at (4, 5), zero at ( three halves , 0)
Discontinuity at (4, 5), zero at (negative three halves , 0)

- anonymous

|dw:1440350394355:dw|

- freckles

so to find the 0 find when the top is 0
that is solve 2x^2+5x-12=0

- anonymous

-4,3/2?

- freckles

ok but one of those is where you have a discontinuity (a hole in this case)
and the other is where you have a zero

- anonymous

So can't you just find the answer now without the y's so it would be A?

- freckles

that is right
a hole at x=-4 and a zero at x=3/2

- anonymous

so A

- freckles

is that the same question you just asked and I said yes "that is right"

- anonymous

yes just making sure because this is an online course and there can be alot of bugs so i wanted to make sure sorry

- freckles

np

- anonymous

is it okay if i tag you in another question?

- anonymous

later?

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