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- anonymous

.

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Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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- anonymous

.

- jamiebookeater

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- Vocaloid

well, sometimes when you solve an equation and end up with an "x" value, the x-value doesn't make the equation true when you plug it back in, because it isn't in the domain of the original function
in short: an extraneous solution is like a "fake" solution that you find that doesn't make the equation true when you plug it back in

- Vocaloid

so, looking at our problem, do you know how to solve for x?

- anonymous

can you subtract 1/(x+4)?

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- anonymous

i like how i tag @vocaloid and3 other people come
xd

- Vocaloid

well, technically yes, but in this case we want to try a different method
this equation doesn't have any real (non-extraneous solutions) but we want to find the "fake" extraneous one

- anonymous

okay then idk

- Vocaloid

so, we multiply everything by (x+4) to get rid of the denominator

- anonymous

oohhhhh okay

- Vocaloid

that gives us
1 + (1/2)(x+4) = 1
can you try solving for x now?

- anonymous

First can you subtract the one?

- Vocaloid

yes, just treat it like a normal equation

- anonymous

how do you multiply 1/2 by x+4

- Vocaloid

you don't have to
after you subtract 1 from both sides, we have
(1/2)(x+4) = 0
now divide both sides by (1/2), what do you get?

- anonymous

x+4=0
lol sorry i knew that i don't know why i forgot
You get -4 right?

- anonymous

so its B?

- Vocaloid

nope, not B, hang with me for a sec ;)
x = -4 is called an "extraneous solution"
although we got x = -4 as an answer, when we plug x = -4 back into the original equation, we can see that the denominator of the first fraction becomes 0, x = -4 isn't a "real" solution

- anonymous

oh A

- Vocaloid

right-o

- anonymous

can u help me with a few more?

- Vocaloid

sure, post a new q and tag me

- anonymous

k

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