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anonymous
 one year ago
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anonymous
 one year ago
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Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2well, sometimes when you solve an equation and end up with an "x" value, the xvalue doesn't make the equation true when you plug it back in, because it isn't in the domain of the original function in short: an extraneous solution is like a "fake" solution that you find that doesn't make the equation true when you plug it back in

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2so, looking at our problem, do you know how to solve for x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you subtract 1/(x+4)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i like how i tag @vocaloid and3 other people come xd

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2well, technically yes, but in this case we want to try a different method this equation doesn't have any real (nonextraneous solutions) but we want to find the "fake" extraneous one

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2so, we multiply everything by (x+4) to get rid of the denominator

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2that gives us 1 + (1/2)(x+4) = 1 can you try solving for x now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First can you subtract the one?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2yes, just treat it like a normal equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you multiply 1/2 by x+4

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2you don't have to after you subtract 1 from both sides, we have (1/2)(x+4) = 0 now divide both sides by (1/2), what do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x+4=0 lol sorry i knew that i don't know why i forgot You get 4 right?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2nope, not B, hang with me for a sec ;) x = 4 is called an "extraneous solution" although we got x = 4 as an answer, when we plug x = 4 back into the original equation, we can see that the denominator of the first fraction becomes 0, x = 4 isn't a "real" solution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u help me with a few more?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2sure, post a new q and tag me
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