anonymous
  • anonymous
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Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Vocaloid
  • Vocaloid
well, sometimes when you solve an equation and end up with an "x" value, the x-value doesn't make the equation true when you plug it back in, because it isn't in the domain of the original function in short: an extraneous solution is like a "fake" solution that you find that doesn't make the equation true when you plug it back in
Vocaloid
  • Vocaloid
so, looking at our problem, do you know how to solve for x?
anonymous
  • anonymous
can you subtract 1/(x+4)?

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anonymous
  • anonymous
i like how i tag @vocaloid and3 other people come xd
Vocaloid
  • Vocaloid
well, technically yes, but in this case we want to try a different method this equation doesn't have any real (non-extraneous solutions) but we want to find the "fake" extraneous one
anonymous
  • anonymous
okay then idk
Vocaloid
  • Vocaloid
so, we multiply everything by (x+4) to get rid of the denominator
anonymous
  • anonymous
oohhhhh okay
Vocaloid
  • Vocaloid
that gives us 1 + (1/2)(x+4) = 1 can you try solving for x now?
anonymous
  • anonymous
First can you subtract the one?
Vocaloid
  • Vocaloid
yes, just treat it like a normal equation
anonymous
  • anonymous
how do you multiply 1/2 by x+4
Vocaloid
  • Vocaloid
you don't have to after you subtract 1 from both sides, we have (1/2)(x+4) = 0 now divide both sides by (1/2), what do you get?
anonymous
  • anonymous
x+4=0 lol sorry i knew that i don't know why i forgot You get -4 right?
anonymous
  • anonymous
so its B?
Vocaloid
  • Vocaloid
nope, not B, hang with me for a sec ;) x = -4 is called an "extraneous solution" although we got x = -4 as an answer, when we plug x = -4 back into the original equation, we can see that the denominator of the first fraction becomes 0, x = -4 isn't a "real" solution
anonymous
  • anonymous
oh A
Vocaloid
  • Vocaloid
right-o
anonymous
  • anonymous
can u help me with a few more?
Vocaloid
  • Vocaloid
sure, post a new q and tag me
anonymous
  • anonymous
k

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