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anonymous
 one year ago
Hey guys i have three questions can you help me? Ive just started college and I need help with this basic algebra.
1. 2a^2+7ab+3b^2
2. 3a^28ab28b^2
3. 36x^212x+1
if you could also explain to me how to do this that would be even better.
anonymous
 one year ago
Hey guys i have three questions can you help me? Ive just started college and I need help with this basic algebra. 1. 2a^2+7ab+3b^2 2. 3a^28ab28b^2 3. 36x^212x+1 if you could also explain to me how to do this that would be even better.

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1quadratic equations: there are 4 method to factor out the quadratic equations

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1i'll go with the easy one Ac method also known as headphone method where you have to find two numbers when you multiply them you should get product of AC and when you add them yo should get middle term

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for the first one I would start it as (2a+ ?b) (a+?b)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i would multiply the 2 and the 3 to get the middle term?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right: find two numbers when you multiply them you should get 6 but when you add them you should get 7ab

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that would be 2a^2+8ab+6b^2 thats not right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay im not following why do i add?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or would this one be prime?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1you should find `two` numbers when you `add` them you should get `middle` term but when you multiply same numbers you should get product of ac what two numbers would you multiply to get 6 but when you add them you get 7 ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right leading coefficient isn't so we have to use factor by groping method dw:1440352936888:dw carry down the first and last term and write the numbers u just found in the middle

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440353069776:dw make a group of `2` terms find the common factor of `1st two terms and then common factor of last 2 terms

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \color{Red}{2a^2+6ab}+\color{blue}{1ab+3b^2}\] what is common in first two terms ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so that makes (a+3b) (2a+b) right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because you factor out the highest factor

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1you can foil it to check your answer (2a+b)(a+3b)=2a^2+7ab+3b^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i foiled it and i got the same answer so its correct let me try the other ab problem the problem 36x^212x+1 I am also still having troubles with

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1do you want to try it first ? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im trying the other ab one first.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay im stuck i have 3a^2 8ab28b^2 I multiplied the 3 by the 28 and got 84 then used the factors 6 and 14 then I got 3a^26ab42ab28b^2 and then i put them in groups like you said (3a^26ab) (42ab 28b^2) then i took 3 and a out of the first group and negative 14b out of the second group then I was left with (3a14b) (a2b) (3a+2b) im confused on what i did wrong

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1oky so by just looking at two numbers i can say thats wrong 6 times 28 =64 okay you have to be careful about signs

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[ \huge\rm 3a^2 \color{Red}{}8ab\color{Red}{}28b^2 \] when you multiply two numbers you should get negative 84 bec `3 times 28=84` and when you add them you should get `8`

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1so 6 times 14 = 84 not negative but what if take 14 times 6 =

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that equals the 8 that is needed

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right thats what we need and thats two number you should put in the middle http://prntscr.com/880qre

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\rm 3a^2+6ab14ab+28b^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay like this 3a^2 14ab+6ab28b^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then i separate them into groups and factor

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i got the correct answer so then it is (3a14b)(a+2b) and i used foil to make sure it was correct and got 3a^28ab28b^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay now on to the last problem this one i have started it as dw:1440355529657:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait hold on i think i just figured it out

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1how do you know it would be one minus and one plus parentheses ? i mean \[\huge\rm (6x?)(x+??)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh wow i feel dumb hahha i didnt realize that the number was supposed to be 1 so i did this dw:1440355938178:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well thank you natasha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356037300:dw that's right !

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1there is anodw:1440356070415:dw 0ther way of factoring quadratic i would like to show that one too ~find factor of first and last term then cross multiply if you get middle term then the numbers you multiplid are factors of the quadratic equation