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anonymous

  • one year ago

???

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  1. amistre64
    • one year ago
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    seems like you want to take a derivative to me

  2. anonymous
    • one year ago
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    I think thats what they're asking, so I would derive that equation to get 8x

  3. amistre64
    • one year ago
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    almost, y' = 8xx'

  4. amistre64
    • one year ago
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    do you know what an implicit is?

  5. amistre64
    • one year ago
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    or rather, just take the derivative of both sides with respect to time, not with respect to x

  6. anonymous
    • one year ago
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    Implicit differentiation?

  7. amistre64
    • one year ago
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    yes \[y = 4x^2+1\] \[\frac{d}{dt}y = \frac{d}{dt}4x^2+\frac{d}{dt}1\] \[\frac{dy}{dt} = \frac{dx}{dt}8x+0\]

  8. amistre64
    • one year ago
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    dx/dt has been defined for us as 2

  9. anonymous
    • one year ago
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    So now I would plug in my values?

  10. amistre64
    • one year ago
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    of course

  11. anonymous
    • one year ago
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    So it is increasing at a rate of 16?

  12. amistre64
    • one year ago
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    correct

  13. amistre64
    • one year ago
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    the key is seeing that x' is not defined as dx/dx in this case, so we take a derivative implicitly with respect to time, and not to x

  14. anonymous
    • one year ago
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    Okay ill remember that for next time, thank you so much for your help!!!!!!

  15. amistre64
    • one year ago
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    good luck

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