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Well, what's the LCD (the common denominator)?
@Hero @mathstudent55 @mathmate @mathmath333
i really just need the fast verion i have three more assignments like this :/
First, we need to understand what the problem is. OS has an equation editor, a draw tool, a way to post pictures, and of course, you can write an expression using numbers, symbols, and parentheses. Since you didn't do any of those, we can't know for sure what your problem is because of the way you wrote it. It can be interpreted in different ways.
Is "fast version" meant to be "answer only" ? lol
Is it one of these? |dw:1440354456001:dw|
x minus 1 over the quantity x times x plus 1 1 minus x over the quantity x times x plus 1 3 minus x over the quantity x times x minus 1 x plus 2 over the quantity x times x minus 1 these are the answers
I'm on an iPad, so I can't use the tools to write the equations :/
and it is the first one XD
You can still use numbers, operation signs, and parentheses.
Ok. The first one. To add fractions, you need a common denominator. First, you need to factor the denominator of the right fraction.
i dont understand
You need to factor \(x^2 + x\). You need to use the distributive property to find out what two factors have a product of \(x^2 + x\).
The distributive property: \(a(b + c) = ab + ac\) In your case, you have \(x^2 + x = x \cdot x + x \cdot 1\) Now compare the right side above with the right side of the distributive property. \(x^2 + x = x(x + 1)\) That is how the right denominator is factored.
Now we need a common denominator. The LCD of x and x(x + 1) is x(x + 1) |dw:1440356356242:dw|
Now we have a common denominator, so we can subtract the fractions. |dw:1440356409379:dw|
That is the final answer. You can;t reduce it because there hare no common factors in the numerator and denominator.