anonymous
  • anonymous
How do you simplify √(8x - 4 )?
Mathematics
schrodinger
  • schrodinger
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ganeshie8
  • ganeshie8
looks you can factor 4 and pull it out of the radical
anonymous
  • anonymous
so I would substitute -1 x 4?
ganeshie8
  • ganeshie8
not sure what you mean, can u do it and show me what you get

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anonymous
  • anonymous
Ok forget the radical for a second and factor this: 8x-4
anonymous
  • anonymous
√(8x - 4) √(8x -(1x4) ?
ganeshie8
  • ganeshie8
looks good, keep going
anonymous
  • anonymous
eek no: take out the 4- 4(2x-1) So now put that under the radical and you can take out the 4 right?
anonymous
  • anonymous
does that make sense?
anonymous
  • anonymous
not really
anonymous
  • anonymous
√(8x - 4) √(8x -(1x4) 2√(8x)?
anonymous
  • anonymous
No, you don't ever get that. You get 8x-4 = 4(2x-1)
anonymous
  • anonymous
And then you get 2 * sqrt(2x-1)
anonymous
  • anonymous
i understand I think
anonymous
  • anonymous
\[2 * \sqrt{2x-1}\] ok then that is basically the farthest you can simplify, have i helped?
anonymous
  • anonymous
unless you have answer choices that say otherwise
anonymous
  • anonymous
yes, but what if I have a larger problem like √11x - 6 ? how would the factoring work then?
TheSmartOne
  • TheSmartOne
^ For that type of question, there would be no factoring to it... If they gave that equal to something, then we could solve for x, but factoring is a no.

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