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anonymous

  • one year ago

How do you simplify √(8x - 4 )?

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  1. ganeshie8
    • one year ago
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    looks you can factor 4 and pull it out of the radical

  2. anonymous
    • one year ago
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    so I would substitute -1 x 4?

  3. ganeshie8
    • one year ago
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    not sure what you mean, can u do it and show me what you get

  4. anonymous
    • one year ago
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    Ok forget the radical for a second and factor this: 8x-4

  5. anonymous
    • one year ago
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    √(8x - 4) √(8x -(1x4) ?

  6. ganeshie8
    • one year ago
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    looks good, keep going

  7. anonymous
    • one year ago
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    eek no: take out the 4- 4(2x-1) So now put that under the radical and you can take out the 4 right?

  8. anonymous
    • one year ago
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    does that make sense?

  9. anonymous
    • one year ago
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    not really

  10. anonymous
    • one year ago
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    √(8x - 4) √(8x -(1x4) 2√(8x)?

  11. anonymous
    • one year ago
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    No, you don't ever get that. You get 8x-4 = 4(2x-1)

  12. anonymous
    • one year ago
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    And then you get 2 * sqrt(2x-1)

  13. anonymous
    • one year ago
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    i understand I think

  14. anonymous
    • one year ago
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    \[2 * \sqrt{2x-1}\] ok then that is basically the farthest you can simplify, have i helped?

  15. anonymous
    • one year ago
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    unless you have answer choices that say otherwise

  16. anonymous
    • one year ago
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    yes, but what if I have a larger problem like √11x - 6 ? how would the factoring work then?

  17. TheSmartOne
    • one year ago
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    ^ For that type of question, there would be no factoring to it... If they gave that equal to something, then we could solve for x, but factoring is a no.

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