anonymous
  • anonymous
Can someone help me with some log problems? I've kinda forgotten how to do them. Log2(5) + log2(x^2-1) - log2(x-1)
Mathematics
chestercat
  • chestercat
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IrishBoy123
  • IrishBoy123
you mean \(log_2(5) + log_2(x^2-1) - log_2(x-1)\) you mean this?
anonymous
  • anonymous
That's right. I'm on an iPad, so I can't use all the tools and such.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
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anonymous
  • anonymous
Is that the simplified version? Or is there more?
CGGURUMANJUNATH
  • CGGURUMANJUNATH
|dw:1440356358452:dw|
anonymous
  • anonymous
Oh yeah, now I remember. And subtraction means division.
IrishBoy123
  • IrishBoy123
\( \log_b(xy) = \log_b(x) + \log_b(y) \!\, \) \( \log_b\!\left(\begin{matrix}\frac{x}{y}\end{matrix}\right) = \log_b(x) - \log_b(y) \)
CGGURUMANJUNATH
  • CGGURUMANJUNATH
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CGGURUMANJUNATH
  • CGGURUMANJUNATH
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CGGURUMANJUNATH
  • CGGURUMANJUNATH
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CGGURUMANJUNATH
  • CGGURUMANJUNATH
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CGGURUMANJUNATH
  • CGGURUMANJUNATH
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CGGURUMANJUNATH
  • CGGURUMANJUNATH
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CGGURUMANJUNATH
  • CGGURUMANJUNATH
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CGGURUMANJUNATH
  • CGGURUMANJUNATH
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IrishBoy123
  • IrishBoy123
@anitasonia98 yeah! as long as it is all in the same base so you can factorise that and see where you go
anonymous
  • anonymous
Thank you! So the final answer is: log2(5) + log2(x+1) Am I right?
IrishBoy123
  • IrishBoy123
how are you seeing drawings on iPad? i have the app and it's useless.
anonymous
  • anonymous
I'm on the Internet version, not the app. I can see the drawings just fine, but they're cut off at the edges.
IrishBoy123
  • IrishBoy123
you can still combine it further.
anonymous
  • anonymous
How do I do that? :o
IrishBoy123
  • IrishBoy123
\(log_2(5) + log_2(x+1)\) ?? \(log_b(xy)=log_b(x)+log_b(y)\) ??
anonymous
  • anonymous
Log2(5) is 32, but you can't simplify the second term any further, right?
anonymous
  • anonymous
Whoops, hold on.
anonymous
  • anonymous
I misread the question. I'm still confused. :o
IrishBoy123
  • IrishBoy123
\(log_2 32 = 5\)
IrishBoy123
  • IrishBoy123
a log is an index or exponent, depending on where you're from
anonymous
  • anonymous
Yeah, that's what I thought it read for a moment, lol.
IrishBoy123
  • IrishBoy123
so combine them to get one log term that will be neatest
anonymous
  • anonymous
So it'll be log2[5(x+1)] then?
IrishBoy123
  • IrishBoy123
i would go with that \(log_2[5(x+1)] \)
anonymous
  • anonymous
Okay! Thank you!
IrishBoy123
  • IrishBoy123
ty!

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