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anonymous

  • one year ago

Can someone help me with some log problems? I've kinda forgotten how to do them. Log2(5) + log2(x^2-1) - log2(x-1)

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  1. IrishBoy123
    • one year ago
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    you mean \(log_2(5) + log_2(x^2-1) - log_2(x-1)\) you mean this?

  2. anonymous
    • one year ago
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    That's right. I'm on an iPad, so I can't use all the tools and such.

  3. CGGURUMANJUNATH
    • one year ago
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    |dw:1440356278906:dw|

  4. anonymous
    • one year ago
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    Is that the simplified version? Or is there more?

  5. CGGURUMANJUNATH
    • one year ago
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    |dw:1440356358452:dw|

  6. anonymous
    • one year ago
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    Oh yeah, now I remember. And subtraction means division.

  7. IrishBoy123
    • one year ago
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    \( \log_b(xy) = \log_b(x) + \log_b(y) \!\, \) \( \log_b\!\left(\begin{matrix}\frac{x}{y}\end{matrix}\right) = \log_b(x) - \log_b(y) \)

  8. CGGURUMANJUNATH
    • one year ago
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    |dw:1440356395663:dw|

  9. CGGURUMANJUNATH
    • one year ago
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    |dw:1440356481967:dw|

  10. CGGURUMANJUNATH
    • one year ago
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    |dw:1440356518914:dw|

  11. CGGURUMANJUNATH
    • one year ago
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    |dw:1440356553577:dw|

  12. CGGURUMANJUNATH
    • one year ago
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    |dw:1440356553577:dw||dw:1440356573409:dw|

  13. CGGURUMANJUNATH
    • one year ago
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    |dw:1440356674444:dw|

  14. CGGURUMANJUNATH
    • one year ago
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    |dw:1440356699957:dw|

  15. CGGURUMANJUNATH
    • one year ago
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    |dw:1440356736755:dw|

  16. IrishBoy123
    • one year ago
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    @anitasonia98 yeah! as long as it is all in the same base so you can factorise that and see where you go

  17. anonymous
    • one year ago
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    Thank you! So the final answer is: log2(5) + log2(x+1) Am I right?

  18. IrishBoy123
    • one year ago
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    how are you seeing drawings on iPad? i have the app and it's useless.

  19. anonymous
    • one year ago
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    I'm on the Internet version, not the app. I can see the drawings just fine, but they're cut off at the edges.

  20. IrishBoy123
    • one year ago
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    you can still combine it further.

  21. anonymous
    • one year ago
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    How do I do that? :o

  22. IrishBoy123
    • one year ago
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    \(log_2(5) + log_2(x+1)\) ?? \(log_b(xy)=log_b(x)+log_b(y)\) ??

  23. anonymous
    • one year ago
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    Log2(5) is 32, but you can't simplify the second term any further, right?

  24. anonymous
    • one year ago
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    Whoops, hold on.

  25. anonymous
    • one year ago
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    I misread the question. I'm still confused. :o

  26. IrishBoy123
    • one year ago
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    \(log_2 32 = 5\)

  27. IrishBoy123
    • one year ago
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    a log is an index or exponent, depending on where you're from

  28. anonymous
    • one year ago
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    Yeah, that's what I thought it read for a moment, lol.

  29. IrishBoy123
    • one year ago
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    so combine them to get one log term that will be neatest

  30. anonymous
    • one year ago
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    So it'll be log2[5(x+1)] then?

  31. IrishBoy123
    • one year ago
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    i would go with that \(log_2[5(x+1)] \)

  32. anonymous
    • one year ago
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    Okay! Thank you!

  33. IrishBoy123
    • one year ago
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    ty!

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