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anonymous
 one year ago
Can someone help me with some log problems? I've kinda forgotten how to do them.
Log2(5) + log2(x^21)  log2(x1)
anonymous
 one year ago
Can someone help me with some log problems? I've kinda forgotten how to do them. Log2(5) + log2(x^21)  log2(x1)

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2you mean \(log_2(5) + log_2(x^21)  log_2(x1)\) you mean this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's right. I'm on an iPad, so I can't use all the tools and such.

CGGURUMANJUNATH
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356278906:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is that the simplified version? Or is there more?

CGGURUMANJUNATH
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356358452:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh yeah, now I remember. And subtraction means division.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2\( \log_b(xy) = \log_b(x) + \log_b(y) \!\, \) \( \log_b\!\left(\begin{matrix}\frac{x}{y}\end{matrix}\right) = \log_b(x)  \log_b(y) \)

CGGURUMANJUNATH
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356395663:dw

CGGURUMANJUNATH
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356481967:dw

CGGURUMANJUNATH
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356518914:dw

CGGURUMANJUNATH
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356553577:dw

CGGURUMANJUNATH
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356553577:dwdw:1440356573409:dw

CGGURUMANJUNATH
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356674444:dw

CGGURUMANJUNATH
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356699957:dw

CGGURUMANJUNATH
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440356736755:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2@anitasonia98 yeah! as long as it is all in the same base so you can factorise that and see where you go

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you! So the final answer is: log2(5) + log2(x+1) Am I right?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2how are you seeing drawings on iPad? i have the app and it's useless.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm on the Internet version, not the app. I can see the drawings just fine, but they're cut off at the edges.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2you can still combine it further.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do I do that? :o

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2\(log_2(5) + log_2(x+1)\) ?? \(log_b(xy)=log_b(x)+log_b(y)\) ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Log2(5) is 32, but you can't simplify the second term any further, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I misread the question. I'm still confused. :o

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2a log is an index or exponent, depending on where you're from

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, that's what I thought it read for a moment, lol.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2so combine them to get one log term that will be neatest

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it'll be log2[5(x+1)] then?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2i would go with that \(log_2[5(x+1)] \)
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