anonymous
  • anonymous
I have another log question :o Log3(x^2)=2log3(4) - 4log3(5)
Mathematics
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anonymous
  • anonymous
I have another log question :o Log3(x^2)=2log3(4) - 4log3(5)
Mathematics
chestercat
  • chestercat
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IrishBoy123
  • IrishBoy123
latexed \(log_3(x^2)=2log_3(4) - 4log_3(5)\) is that right?
anonymous
  • anonymous
Yep, that's right!
welshfella
  • welshfella
by the laws of logs log3 x^2 = log3 4^2 - log3 4^5 log3 x^2 = log3 (4^2 / 4^5) can you continue?

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anonymous
  • anonymous
How did you get 4^5? Isn't it 5^4?
welshfella
  • welshfella
** ooops sorry that is 5^4 not 4^5
anonymous
  • anonymous
I got to where you are, and I understand it, but now I'm unsure of how to continue from there :o
welshfella
  • welshfella
this is easy now..
anonymous
  • anonymous
:/ Still not sure of how to proceed, sorry.
welshfella
  • welshfella
if a^x = a^y what is the relation between x and y?
anonymous
  • anonymous
They're equal to each other, right?
welshfella
  • welshfella
yes
anonymous
  • anonymous
x^2 = 16/625?
welshfella
  • welshfella
yes
anonymous
  • anonymous
so the final answer is x=4/25, right? Just want to make sure.
welshfella
  • welshfella
right - what about -4/25?
welshfella
  • welshfella
catch question..
anonymous
  • anonymous
Since it's log, you can't have a negative answer..
anonymous
  • anonymous
...right?
IrishBoy123
  • IrishBoy123
why not put \(-\frac{4}{25}\) into the original equation....? see if it works you cruel man, @welshfella !!
welshfella
  • welshfella
i know!!

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