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anonymous

  • one year ago

I have another log question :o Log3(x^2)=2log3(4) - 4log3(5)

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  1. IrishBoy123
    • one year ago
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    latexed \(log_3(x^2)=2log_3(4) - 4log_3(5)\) is that right?

  2. anonymous
    • one year ago
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    Yep, that's right!

  3. welshfella
    • one year ago
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    by the laws of logs log3 x^2 = log3 4^2 - log3 4^5 log3 x^2 = log3 (4^2 / 4^5) can you continue?

  4. anonymous
    • one year ago
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    How did you get 4^5? Isn't it 5^4?

  5. welshfella
    • one year ago
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    ** ooops sorry that is 5^4 not 4^5

  6. anonymous
    • one year ago
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    I got to where you are, and I understand it, but now I'm unsure of how to continue from there :o

  7. welshfella
    • one year ago
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    this is easy now..

  8. anonymous
    • one year ago
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    :/ Still not sure of how to proceed, sorry.

  9. welshfella
    • one year ago
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    if a^x = a^y what is the relation between x and y?

  10. anonymous
    • one year ago
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    They're equal to each other, right?

  11. welshfella
    • one year ago
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    yes

  12. anonymous
    • one year ago
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    x^2 = 16/625?

  13. welshfella
    • one year ago
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    yes

  14. anonymous
    • one year ago
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    so the final answer is x=4/25, right? Just want to make sure.

  15. welshfella
    • one year ago
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    right - what about -4/25?

  16. welshfella
    • one year ago
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    catch question..

  17. anonymous
    • one year ago
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    Since it's log, you can't have a negative answer..

  18. anonymous
    • one year ago
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    ...right?

  19. IrishBoy123
    • one year ago
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    why not put \(-\frac{4}{25}\) into the original equation....? see if it works you cruel man, @welshfella !!

  20. welshfella
    • one year ago
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    i know!!

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