Pre-calculus 12 question!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

- korosh23

Pre-calculus 12 question!

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- korosh23

##### 1 Attachment

- Vocaloid

well, the height of the rectangle is given by the equation y = 9 - x^2
and the width is 2x

- korosh23

Ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- Vocaloid

so area = ?

- korosh23

I know how to get the area, but how do you know the height?

- korosh23

- Vocaloid

well, think of it this way:
on the x-y coordinate plane, the x value tells you how far to the right or left to go, and the y-value tells you how far up or down to go, correct?
since we want the height of the rectangle, it naturally follows that we want the y value

- korosh23

yes correct

- Vocaloid

so, we're given the equation y = 9 - x^2, so that's our height

- korosh23

but the height of the rectangle is far smaller than the original prabola

- Vocaloid

nope, not necessarily, remember that x is not a fixed value
if we make x something super small, like 0.00001, then the height of the rectangle is almost the height of the parabola
the point is that x changes

- korosh23

ok I got this, and about the width, it looks like 4x to me. How is it 2x?

- Vocaloid

well, think of it this way.
let's try splitting the rectangle in half down the y-axis, like this:
|dw:1440359170630:dw|

- korosh23

Oh I see :) Yes and as we know negative value does not have any meaning in area.

- Vocaloid

nope, that's not quite the point I was getting at...

- korosh23

ok go ahead

- Vocaloid

|dw:1440359429185:dw|
would you agree that the distance marked is equal to x?

- korosh23

yes

- Vocaloid

so, all we have to do now is add the other half of the rectangle back in.
|dw:1440359485663:dw|

- Vocaloid

making our width equal to 2x

- korosh23

oh I see

- Vocaloid

any other questions?

- korosh23

Everything is good. Thank you for clarifying this to me @Vocaloid

Looking for something else?

Not the answer you are looking for? Search for more explanations.