korosh23
  • korosh23
Pre-calculus 12 question!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
korosh23
  • korosh23
1 Attachment
Vocaloid
  • Vocaloid
well, the height of the rectangle is given by the equation y = 9 - x^2 and the width is 2x
korosh23
  • korosh23
Ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Vocaloid
  • Vocaloid
so area = ?
korosh23
  • korosh23
I know how to get the area, but how do you know the height?
korosh23
  • korosh23
@Vocaloid
Vocaloid
  • Vocaloid
well, think of it this way: on the x-y coordinate plane, the x value tells you how far to the right or left to go, and the y-value tells you how far up or down to go, correct? since we want the height of the rectangle, it naturally follows that we want the y value
korosh23
  • korosh23
yes correct
Vocaloid
  • Vocaloid
so, we're given the equation y = 9 - x^2, so that's our height
korosh23
  • korosh23
but the height of the rectangle is far smaller than the original prabola
Vocaloid
  • Vocaloid
nope, not necessarily, remember that x is not a fixed value if we make x something super small, like 0.00001, then the height of the rectangle is almost the height of the parabola the point is that x changes
korosh23
  • korosh23
ok I got this, and about the width, it looks like 4x to me. How is it 2x?
Vocaloid
  • Vocaloid
well, think of it this way. let's try splitting the rectangle in half down the y-axis, like this: |dw:1440359170630:dw|
korosh23
  • korosh23
Oh I see :) Yes and as we know negative value does not have any meaning in area.
Vocaloid
  • Vocaloid
nope, that's not quite the point I was getting at...
korosh23
  • korosh23
ok go ahead
Vocaloid
  • Vocaloid
|dw:1440359429185:dw| would you agree that the distance marked is equal to x?
korosh23
  • korosh23
yes
Vocaloid
  • Vocaloid
so, all we have to do now is add the other half of the rectangle back in. |dw:1440359485663:dw|
Vocaloid
  • Vocaloid
making our width equal to 2x
korosh23
  • korosh23
oh I see
Vocaloid
  • Vocaloid
any other questions?
korosh23
  • korosh23
Everything is good. Thank you for clarifying this to me @Vocaloid

Looking for something else?

Not the answer you are looking for? Search for more explanations.